Metamath Proof Explorer


Theorem ldualkrsc

Description: The kernel of a nonzero scalar product of a functional equals the kernel of the functional. (Contributed by NM, 28-Dec-2014)

Ref Expression
Hypotheses ldualkrsc.r ⊢ R = Scalar ⁡ W
ldualkrsc.k ⊢ K = Base R
ldualkrsc.o ⊢ 0 ˙ = 0 R
ldualkrsc.f ⊢ F = LFnl ⁡ W
ldualkrsc.l ⊢ L = LKer ⁡ W
ldualkrsc.d ⊢ D = LDual ⁡ W
ldualkrsc.s ⊢ · ˙ = ⋅ D
ldualkrsc.w ⊢ φ → W ∈ LVec
ldualkrsc.g ⊢ φ → G ∈ F
ldualkrsc.x ⊢ φ → X ∈ K
ldualkrsc.e ⊢ φ → X ≠ 0 ˙
Assertion ldualkrsc ⊢ φ → L ⁡ X · ˙ G = L ⁡ G

Proof

Step Hyp Ref Expression
1 ldualkrsc.r ⊢ R = Scalar ⁡ W
2 ldualkrsc.k ⊢ K = Base R
3 ldualkrsc.o ⊢ 0 ˙ = 0 R
4 ldualkrsc.f ⊢ F = LFnl ⁡ W
5 ldualkrsc.l ⊢ L = LKer ⁡ W
6 ldualkrsc.d ⊢ D = LDual ⁡ W
7 ldualkrsc.s ⊢ · ˙ = ⋅ D
8 ldualkrsc.w ⊢ φ → W ∈ LVec
9 ldualkrsc.g ⊢ φ → G ∈ F
10 ldualkrsc.x ⊢ φ → X ∈ K
11 ldualkrsc.e ⊢ φ → X ≠ 0 ˙
12 eqid ⊢ Base W = Base W
13 eqid ⊢ ⋅ R = ⋅ R
14 4 12 1 2 13 6 7 8 10 9 ldualvs ⊢ φ → X · ˙ G = G ⋅ R f Base W × X
15 14 fveq2d ⊢ φ → L ⁡ X · ˙ G = L ⁡ G ⋅ R f Base W × X
16 12 1 2 13 4 5 8 9 10 3 11 lkrsc ⊢ φ → L ⁡ G ⋅ R f Base W × X = L ⁡ G
17 15 16 eqtrd ⊢ φ → L ⁡ X · ˙ G = L ⁡ G