Metamath Proof Explorer


Theorem le2halvesd

Description: A sum is less than the whole if each term is less than half. (Contributed by Thierry Arnoux, 29-Nov-2017)

Ref Expression
Hypotheses le2halvesd.1 ⊢ φ → A ∈ ℝ
le2halvesd.2 ⊢ φ → B ∈ ℝ
le2halvesd.3 ⊢ φ → C ∈ ℝ
le2halvesd.4 ⊢ φ → A ≤ C 2
le2halvesd.5 ⊢ φ → B ≤ C 2
Assertion le2halvesd ⊢ φ → A + B ≤ C

Proof

Step Hyp Ref Expression
1 le2halvesd.1 ⊢ φ → A ∈ ℝ
2 le2halvesd.2 ⊢ φ → B ∈ ℝ
3 le2halvesd.3 ⊢ φ → C ∈ ℝ
4 le2halvesd.4 ⊢ φ → A ≤ C 2
5 le2halvesd.5 ⊢ φ → B ≤ C 2
6 3 rehalfcld ⊢ φ → C 2 ∈ ℝ
7 1 2 6 6 4 5 le2addd ⊢ φ → A + B ≤ C 2 + C 2
8 3 recnd ⊢ φ → C ∈ ℂ
9 8 2halvesd ⊢ φ → C 2 + C 2 = C
10 7 9 breqtrd ⊢ φ → A + B ≤ C