Metamath Proof Explorer


Theorem leat

Description: A poset element less than or equal to an atom equals either zero or the atom. (Contributed by NM, 15-Oct-2013)

Ref Expression
Hypotheses leatom.b ⊢ B = Base K
leatom.l ⊢ ≤ ˙ = ≤ K
leatom.z ⊢ 0 ˙ = 0. ⁡ K
leatom.a ⊢ A = Atoms ⁡ K
Assertion leat ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X = P ∨ X = 0 ˙

Proof

Step Hyp Ref Expression
1 leatom.b ⊢ B = Base K
2 leatom.l ⊢ ≤ ˙ = ≤ K
3 leatom.z ⊢ 0 ˙ = 0. ⁡ K
4 leatom.a ⊢ A = Atoms ⁡ K
5 1 2 3 4 leatb ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A → X ≤ ˙ P ↔ X = P ∨ X = 0 ˙
6 5 biimpa ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X = P ∨ X = 0 ˙