Metamath Proof Explorer


Theorem leat3

Description: A poset element less than or equal to an atom is either an atom or zero. (Contributed by NM, 2-Dec-2012)

Ref Expression
Hypotheses leatom.b ⊢ B = Base K
leatom.l ⊢ ≤ ˙ = ≤ K
leatom.z ⊢ 0 ˙ = 0. ⁡ K
leatom.a ⊢ A = Atoms ⁡ K
Assertion leat3 ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X ∈ A ∨ X = 0 ˙

Proof

Step Hyp Ref Expression
1 leatom.b ⊢ B = Base K
2 leatom.l ⊢ ≤ ˙ = ≤ K
3 leatom.z ⊢ 0 ˙ = 0. ⁡ K
4 leatom.a ⊢ A = Atoms ⁡ K
5 1 2 3 4 leat ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X = P ∨ X = 0 ˙
6 simpl3 ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → P ∈ A
7 eleq1a ⊢ P ∈ A → X = P → X ∈ A
8 6 7 syl ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X = P → X ∈ A
9 8 orim1d ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X = P ∨ X = 0 ˙ → X ∈ A ∨ X = 0 ˙
10 5 9 mpd ⊢ K ∈ OP ∧ X ∈ B ∧ P ∈ A ∧ X ≤ ˙ P → X ∈ A ∨ X = 0 ˙