Metamath Proof Explorer


Theorem lflsc0N

Description: The scalar product with the zero functional is the zero functional. (Contributed by NM, 7-Oct-2014) (New usage is discouraged.)

Ref Expression
Hypotheses lflsc0.v ⊢ V = Base W
lflsc0.d ⊢ D = Scalar ⁡ W
lflsc0.k ⊢ K = Base D
lflsc0.t ⊢ · ˙ = ⋅ D
lflsc0.o ⊢ 0 ˙ = 0 D
lflsc0.w ⊢ φ → W ∈ LMod
lflsc0.x ⊢ φ → X ∈ K
Assertion lflsc0N ⊢ φ → V × 0 ˙ · ˙ f V × X = V × 0 ˙

Proof

Step Hyp Ref Expression
1 lflsc0.v ⊢ V = Base W
2 lflsc0.d ⊢ D = Scalar ⁡ W
3 lflsc0.k ⊢ K = Base D
4 lflsc0.t ⊢ · ˙ = ⋅ D
5 lflsc0.o ⊢ 0 ˙ = 0 D
6 lflsc0.w ⊢ φ → W ∈ LMod
7 lflsc0.x ⊢ φ → X ∈ K
8 1 fvexi ⊢ V ∈ V
9 8 a1i ⊢ φ → V ∈ V
10 2 lmodring ⊢ W ∈ LMod → D ∈ Ring
11 6 10 syl ⊢ φ → D ∈ Ring
12 3 5 ring0cl ⊢ D ∈ Ring → 0 ˙ ∈ K
13 11 12 syl ⊢ φ → 0 ˙ ∈ K
14 9 13 7 ofc12 ⊢ φ → V × 0 ˙ · ˙ f V × X = V × 0 ˙ · ˙ X
15 3 4 5 ringlz ⊢ D ∈ Ring ∧ X ∈ K → 0 ˙ · ˙ X = 0 ˙
16 11 7 15 syl2anc ⊢ φ → 0 ˙ · ˙ X = 0 ˙
17 16 sneqd ⊢ φ → 0 ˙ · ˙ X = 0 ˙
18 17 xpeq2d ⊢ φ → V × 0 ˙ · ˙ X = V × 0 ˙
19 14 18 eqtrd ⊢ φ → V × 0 ˙ · ˙ f V × X = V × 0 ˙