Metamath Proof Explorer


Theorem lgsdinn0

Description: Variation on lgsdi valid for all M , N but only for positive A . (The exact location of the failure of this law is for A = -u 1 , M = 0 , and some N in which case ( -u 1 /L 0 ) = 1 but ( -u 1 /L N ) = -u 1 when -u 1 is not a quadratic residue mod N .) (Contributed by Mario Carneiro, 28-Apr-2016)

Ref Expression
Assertion lgsdinn0 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L M ⋅ N = A / L M ⁢ A / L N

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ x = N → A / L x = A / L N
2 1 oveq1d ⊢ x = N → A / L x ⁢ A / L 0 = A / L N ⁢ A / L 0
3 2 eqeq2d ⊢ x = N → A / L 0 = A / L x ⁢ A / L 0 ↔ A / L 0 = A / L N ⁢ A / L 0
4 sq1 ⊢ 1 2 = 1
5 4 eqeq2i ⊢ A 2 = 1 2 ↔ A 2 = 1
6 nn0re ⊢ A ∈ ℕ 0 → A ∈ ℝ
7 nn0ge0 ⊢ A ∈ ℕ 0 → 0 ≤ A
8 1re ⊢ 1 ∈ ℝ
9 0le1 ⊢ 0 ≤ 1
10 sq11 ⊢ A ∈ ℝ ∧ 0 ≤ A ∧ 1 ∈ ℝ ∧ 0 ≤ 1 → A 2 = 1 2 ↔ A = 1
11 8 9 10 mpanr12 ⊢ A ∈ ℝ ∧ 0 ≤ A → A 2 = 1 2 ↔ A = 1
12 6 7 11 syl2anc ⊢ A ∈ ℕ 0 → A 2 = 1 2 ↔ A = 1
13 12 adantr ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A 2 = 1 2 ↔ A = 1
14 5 13 bitr3id ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A 2 = 1 ↔ A = 1
15 14 biimpa ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A = 1
16 15 oveq1d ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L x = 1 / L x
17 1lgs ⊢ x ∈ ℤ → 1 / L x = 1
18 17 ad2antlr ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → 1 / L x = 1
19 16 18 eqtrd ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L x = 1
20 19 oveq1d ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L x ⁢ A / L 0 = 1 ⁢ A / L 0
21 nn0z ⊢ A ∈ ℕ 0 → A ∈ ℤ
22 21 ad2antrr ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A ∈ ℤ
23 0z ⊢ 0 ∈ ℤ
24 lgscl ⊢ A ∈ ℤ ∧ 0 ∈ ℤ → A / L 0 ∈ ℤ
25 22 23 24 sylancl ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L 0 ∈ ℤ
26 25 zcnd ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L 0 ∈ ℂ
27 26 mullidd ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → 1 ⁢ A / L 0 = A / L 0
28 20 27 eqtr2d ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 = 1 → A / L 0 = A / L x ⁢ A / L 0
29 lgscl ⊢ A ∈ ℤ ∧ x ∈ ℤ → A / L x ∈ ℤ
30 21 29 sylan ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A / L x ∈ ℤ
31 30 zcnd ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A / L x ∈ ℂ
32 31 adantr ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 ≠ 1 → A / L x ∈ ℂ
33 32 mul01d ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 ≠ 1 → A / L x ⋅ 0 = 0
34 21 adantr ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A ∈ ℤ
35 lgs0 ⊢ A ∈ ℤ → A / L 0 = if A 2 = 1 1 0
36 34 35 syl ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A / L 0 = if A 2 = 1 1 0
37 ifnefalse ⊢ A 2 ≠ 1 → if A 2 = 1 1 0 = 0
38 36 37 sylan9eq ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 ≠ 1 → A / L 0 = 0
39 38 oveq2d ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 ≠ 1 → A / L x ⁢ A / L 0 = A / L x ⋅ 0
40 33 39 38 3eqtr4rd ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ ∧ A 2 ≠ 1 → A / L 0 = A / L x ⁢ A / L 0
41 28 40 pm2.61dane ⊢ A ∈ ℕ 0 ∧ x ∈ ℤ → A / L 0 = A / L x ⁢ A / L 0
42 41 ralrimiva ⊢ A ∈ ℕ 0 → ∀ x ∈ ℤ A / L 0 = A / L x ⁢ A / L 0
43 42 3ad2ant1 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → ∀ x ∈ ℤ A / L 0 = A / L x ⁢ A / L 0
44 simp3 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → N ∈ ℤ
45 3 43 44 rspcdva ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L 0 = A / L N ⁢ A / L 0
46 45 adantr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L 0 = A / L N ⁢ A / L 0
47 21 3ad2ant1 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A ∈ ℤ
48 47 23 24 sylancl ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L 0 ∈ ℤ
49 48 zcnd ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L 0 ∈ ℂ
50 49 adantr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L 0 ∈ ℂ
51 lgscl ⊢ A ∈ ℤ ∧ N ∈ ℤ → A / L N ∈ ℤ
52 47 44 51 syl2anc ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L N ∈ ℤ
53 52 zcnd ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L N ∈ ℂ
54 53 adantr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L N ∈ ℂ
55 50 54 mulcomd ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L 0 ⁢ A / L N = A / L N ⁢ A / L 0
56 46 55 eqtr4d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L 0 = A / L 0 ⁢ A / L N
57 oveq1 ⊢ M = 0 → M ⋅ N = 0 ⋅ N
58 44 zcnd ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → N ∈ ℂ
59 58 mul02d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → 0 ⋅ N = 0
60 57 59 sylan9eqr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → M ⋅ N = 0
61 60 oveq2d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L M ⋅ N = A / L 0
62 simpr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → M = 0
63 62 oveq2d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L M = A / L 0
64 63 oveq1d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L M ⁢ A / L N = A / L 0 ⁢ A / L N
65 56 61 64 3eqtr4d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M = 0 → A / L M ⋅ N = A / L M ⁢ A / L N
66 oveq2 ⊢ x = M → A / L x = A / L M
67 66 oveq1d ⊢ x = M → A / L x ⁢ A / L 0 = A / L M ⁢ A / L 0
68 67 eqeq2d ⊢ x = M → A / L 0 = A / L x ⁢ A / L 0 ↔ A / L 0 = A / L M ⁢ A / L 0
69 simp2 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → M ∈ ℤ
70 68 43 69 rspcdva ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L 0 = A / L M ⁢ A / L 0
71 70 adantr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → A / L 0 = A / L M ⁢ A / L 0
72 oveq2 ⊢ N = 0 → M ⋅ N = M ⋅ 0
73 69 zcnd ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → M ∈ ℂ
74 73 mul01d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → M ⋅ 0 = 0
75 72 74 sylan9eqr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → M ⋅ N = 0
76 75 oveq2d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → A / L M ⋅ N = A / L 0
77 simpr ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → N = 0
78 77 oveq2d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → A / L N = A / L 0
79 78 oveq2d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → A / L M ⁢ A / L N = A / L M ⁢ A / L 0
80 71 76 79 3eqtr4d ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ N = 0 → A / L M ⋅ N = A / L M ⁢ A / L N
81 lgsdi ⊢ A ∈ ℤ ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M ≠ 0 ∧ N ≠ 0 → A / L M ⋅ N = A / L M ⁢ A / L N
82 21 81 syl3anl1 ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ ∧ M ≠ 0 ∧ N ≠ 0 → A / L M ⋅ N = A / L M ⁢ A / L N
83 65 80 82 pm2.61da2ne ⊢ A ∈ ℕ 0 ∧ M ∈ ℤ ∧ N ∈ ℤ → A / L M ⋅ N = A / L M ⁢ A / L N