Metamath Proof Explorer


Theorem lgsneg1

Description: The Legendre symbol for nonnegative first parameter is unchanged by negation of the second. (Contributed by Mario Carneiro, 4-Feb-2015)

Ref Expression
Assertion lgsneg1 ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ → A / L -N = A / L N

Proof

Step Hyp Ref Expression
1 neg0 ⊢ − 0 = 0
2 simpr ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N = 0 → N = 0
3 2 negeqd ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N = 0 → − N = − 0
4 1 3 2 3eqtr4a ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N = 0 → − N = N
5 4 oveq2d ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N = 0 → A / L -N = A / L N
6 nn0z ⊢ A ∈ ℕ 0 → A ∈ ℤ
7 lgsneg ⊢ A ∈ ℤ ∧ N ∈ ℤ ∧ N ≠ 0 → A / L -N = if A < 0 − 1 1 ⁢ A / L N
8 6 7 syl3an1 ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A / L -N = if A < 0 − 1 1 ⁢ A / L N
9 nn0nlt0 ⊢ A ∈ ℕ 0 → ¬ A < 0
10 9 3ad2ant1 ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → ¬ A < 0
11 10 iffalsed ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → if A < 0 − 1 1 = 1
12 11 oveq1d ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → if A < 0 − 1 1 ⁢ A / L N = 1 ⁢ A / L N
13 6 3ad2ant1 ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A ∈ ℤ
14 simp2 ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → N ∈ ℤ
15 lgscl ⊢ A ∈ ℤ ∧ N ∈ ℤ → A / L N ∈ ℤ
16 13 14 15 syl2anc ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A / L N ∈ ℤ
17 16 zcnd ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A / L N ∈ ℂ
18 17 mullidd ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → 1 ⁢ A / L N = A / L N
19 8 12 18 3eqtrd ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A / L -N = A / L N
20 19 3expa ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ ∧ N ≠ 0 → A / L -N = A / L N
21 5 20 pm2.61dane ⊢ A ∈ ℕ 0 ∧ N ∈ ℤ → A / L -N = A / L N