Metamath Proof Explorer


Theorem lhpm0atN

Description: If the meet of a lattice hyperplane with a nonzero element is zero, the element is an atom. (Contributed by NM, 28-Apr-2014) (New usage is discouraged.)

Ref Expression
Hypotheses lhpm0at.b ⊢ B = Base K
lhpm0at.m ⊢ ∧ ˙ = meet ⁡ K
lhpm0at.o ⊢ 0 ˙ = 0. ⁡ K
lhpm0at.a ⊢ A = Atoms ⁡ K
lhpm0at.h ⊢ H = LHyp ⁡ K
Assertion lhpm0atN ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∈ A

Proof

Step Hyp Ref Expression
1 lhpm0at.b ⊢ B = Base K
2 lhpm0at.m ⊢ ∧ ˙ = meet ⁡ K
3 lhpm0at.o ⊢ 0 ˙ = 0. ⁡ K
4 lhpm0at.a ⊢ A = Atoms ⁡ K
5 lhpm0at.h ⊢ H = LHyp ⁡ K
6 simpr3 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∧ ˙ W = 0 ˙
7 simpl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → K ∈ HL ∧ W ∈ H
8 simpr1 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∈ B
9 simpr2 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ≠ 0 ˙
10 hllat ⊢ K ∈ HL → K ∈ Lat
11 10 ad2antrr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → K ∈ Lat
12 1 5 lhpbase ⊢ W ∈ H → W ∈ B
13 12 ad2antlr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → W ∈ B
14 eqid ⊢ ≤ K = ≤ K
15 1 14 2 latleeqm1 ⊢ K ∈ Lat ∧ X ∈ B ∧ W ∈ B → X ≤ K W ↔ X ∧ ˙ W = X
16 11 8 13 15 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ≤ K W ↔ X ∧ ˙ W = X
17 16 biimpa ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ ∧ X ≤ K W → X ∧ ˙ W = X
18 simplr3 ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ ∧ X ≤ K W → X ∧ ˙ W = 0 ˙
19 17 18 eqtr3d ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ ∧ X ≤ K W → X = 0 ˙
20 19 ex ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ≤ K W → X = 0 ˙
21 20 necon3ad ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ≠ 0 ˙ → ¬ X ≤ K W
22 9 21 mpd ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → ¬ X ≤ K W
23 eqid ⊢ ⋖ K = ⋖ K
24 1 14 2 23 5 lhpmcvr ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ ¬ X ≤ K W → X ∧ ˙ W ⋖ K X
25 7 8 22 24 syl12anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∧ ˙ W ⋖ K X
26 6 25 eqbrtrrd ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → 0 ˙ ⋖ K X
27 simpll ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → K ∈ HL
28 1 3 23 4 isat2 ⊢ K ∈ HL ∧ X ∈ B → X ∈ A ↔ 0 ˙ ⋖ K X
29 27 8 28 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∈ A ↔ 0 ˙ ⋖ K X
30 26 29 mpbird ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ B ∧ X ≠ 0 ˙ ∧ X ∧ ˙ W = 0 ˙ → X ∈ A