Metamath Proof Explorer


Theorem lindspropd

Description: Property deduction for linearly independent sets. (Contributed by Thierry Arnoux, 16-Jul-2023)

Ref Expression
Hypotheses lindfpropd.1 ⊢ φ → Base K = Base L
lindfpropd.2 ⊢ φ → Base Scalar ⁡ K = Base Scalar ⁡ L
lindfpropd.3 ⊢ φ → 0 Scalar ⁡ K = 0 Scalar ⁡ L
lindfpropd.4 ⊢ φ ∧ x ∈ Base K ∧ y ∈ Base K → x + K y = x + L y
lindfpropd.5 ⊢ φ ∧ x ∈ Base Scalar ⁡ K ∧ y ∈ Base K → x ⋅ K y ∈ Base K
lindfpropd.6 ⊢ φ ∧ x ∈ Base Scalar ⁡ K ∧ y ∈ Base K → x ⋅ K y = x ⋅ L y
lindfpropd.k ⊢ φ → K ∈ V
lindfpropd.l ⊢ φ → L ∈ W
Assertion lindspropd ⊢ φ → LIndS ⁡ K = LIndS ⁡ L

Proof

Step Hyp Ref Expression
1 lindfpropd.1 ⊢ φ → Base K = Base L
2 lindfpropd.2 ⊢ φ → Base Scalar ⁡ K = Base Scalar ⁡ L
3 lindfpropd.3 ⊢ φ → 0 Scalar ⁡ K = 0 Scalar ⁡ L
4 lindfpropd.4 ⊢ φ ∧ x ∈ Base K ∧ y ∈ Base K → x + K y = x + L y
5 lindfpropd.5 ⊢ φ ∧ x ∈ Base Scalar ⁡ K ∧ y ∈ Base K → x ⋅ K y ∈ Base K
6 lindfpropd.6 ⊢ φ ∧ x ∈ Base Scalar ⁡ K ∧ y ∈ Base K → x ⋅ K y = x ⋅ L y
7 lindfpropd.k ⊢ φ → K ∈ V
8 lindfpropd.l ⊢ φ → L ∈ W
9 1 sseq2d ⊢ φ → z ⊆ Base K ↔ z ⊆ Base L
10 vex ⊢ z ∈ V
11 10 a1i ⊢ φ → z ∈ V
12 11 resiexd ⊢ φ → I ↾ z ∈ V
13 1 2 3 4 5 6 7 8 12 lindfpropd ⊢ φ → I ↾ z LIndF K ↔ I ↾ z LIndF L
14 9 13 anbi12d ⊢ φ → z ⊆ Base K ∧ I ↾ z LIndF K ↔ z ⊆ Base L ∧ I ↾ z LIndF L
15 eqid ⊢ Base K = Base K
16 15 islinds ⊢ K ∈ V → z ∈ LIndS ⁡ K ↔ z ⊆ Base K ∧ I ↾ z LIndF K
17 7 16 syl ⊢ φ → z ∈ LIndS ⁡ K ↔ z ⊆ Base K ∧ I ↾ z LIndF K
18 eqid ⊢ Base L = Base L
19 18 islinds ⊢ L ∈ W → z ∈ LIndS ⁡ L ↔ z ⊆ Base L ∧ I ↾ z LIndF L
20 8 19 syl ⊢ φ → z ∈ LIndS ⁡ L ↔ z ⊆ Base L ∧ I ↾ z LIndF L
21 14 17 20 3bitr4d ⊢ φ → z ∈ LIndS ⁡ K ↔ z ∈ LIndS ⁡ L
22 21 eqrdv ⊢ φ → LIndS ⁡ K = LIndS ⁡ L