Metamath Proof Explorer


Theorem lkr0f2

Description: The kernel of the zero functional is the set of all vectors. (Contributed by NM, 4-Feb-2015)

Ref Expression
Hypotheses lkr0f2.v ⊢ V = Base W
lkr0f2.f ⊢ F = LFnl ⁡ W
lkr0f2.k ⊢ K = LKer ⁡ W
lkr0f2.d ⊢ D = LDual ⁡ W
lkr0f2.o ⊢ 0 ˙ = 0 D
lkr0f2.w ⊢ φ → W ∈ LMod
lkr0f2.g ⊢ φ → G ∈ F
Assertion lkr0f2 ⊢ φ → K ⁡ G = V ↔ G = 0 ˙

Proof

Step Hyp Ref Expression
1 lkr0f2.v ⊢ V = Base W
2 lkr0f2.f ⊢ F = LFnl ⁡ W
3 lkr0f2.k ⊢ K = LKer ⁡ W
4 lkr0f2.d ⊢ D = LDual ⁡ W
5 lkr0f2.o ⊢ 0 ˙ = 0 D
6 lkr0f2.w ⊢ φ → W ∈ LMod
7 lkr0f2.g ⊢ φ → G ∈ F
8 eqid ⊢ Scalar ⁡ W = Scalar ⁡ W
9 eqid ⊢ 0 Scalar ⁡ W = 0 Scalar ⁡ W
10 8 9 1 2 3 lkr0f ⊢ W ∈ LMod ∧ G ∈ F → K ⁡ G = V ↔ G = V × 0 Scalar ⁡ W
11 6 7 10 syl2anc ⊢ φ → K ⁡ G = V ↔ G = V × 0 Scalar ⁡ W
12 1 8 9 4 5 6 ldual0v ⊢ φ → 0 ˙ = V × 0 Scalar ⁡ W
13 12 eqeq2d ⊢ φ → G = 0 ˙ ↔ G = V × 0 Scalar ⁡ W
14 11 13 bitr4d ⊢ φ → K ⁡ G = V ↔ G = 0 ˙