Metamath Proof Explorer


Theorem lncvrelatN

Description: A lattice element covered by a line is an atom. (Contributed by NM, 28-Apr-2012) (New usage is discouraged.)

Ref Expression
Hypotheses lncvrelat.b ⊢ B = Base K
lncvrelat.c ⊢ C = ⋖ K
lncvrelat.a ⊢ A = Atoms ⁡ K
lncvrelat.n ⊢ N = Lines ⁡ K
lncvrelat.m ⊢ M = pmap ⁡ K
Assertion lncvrelatN ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ M ⁡ X ∈ N ∧ P C X → P ∈ A

Proof

Step Hyp Ref Expression
1 lncvrelat.b ⊢ B = Base K
2 lncvrelat.c ⊢ C = ⋖ K
3 lncvrelat.a ⊢ A = Atoms ⁡ K
4 lncvrelat.n ⊢ N = Lines ⁡ K
5 lncvrelat.m ⊢ M = pmap ⁡ K
6 hllat ⊢ K ∈ HL → K ∈ Lat
7 6 3ad2ant1 ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B → K ∈ Lat
8 eqid ⊢ join ⁡ K = join ⁡ K
9 8 3 4 5 isline2 ⊢ K ∈ Lat → M ⁡ X ∈ N ↔ ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ M ⁡ X = M ⁡ q join ⁡ K r
10 7 9 syl ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B → M ⁡ X ∈ N ↔ ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ M ⁡ X = M ⁡ q join ⁡ K r
11 simpll1 ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → K ∈ HL
12 simpll2 ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → X ∈ B
13 11 6 syl ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → K ∈ Lat
14 simplrl ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → q ∈ A
15 1 3 atbase ⊢ q ∈ A → q ∈ B
16 14 15 syl ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → q ∈ B
17 simplrr ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → r ∈ A
18 1 3 atbase ⊢ r ∈ A → r ∈ B
19 17 18 syl ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → r ∈ B
20 1 8 latjcl ⊢ K ∈ Lat ∧ q ∈ B ∧ r ∈ B → q join ⁡ K r ∈ B
21 13 16 19 20 syl3anc ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → q join ⁡ K r ∈ B
22 1 5 pmap11 ⊢ K ∈ HL ∧ X ∈ B ∧ q join ⁡ K r ∈ B → M ⁡ X = M ⁡ q join ⁡ K r ↔ X = q join ⁡ K r
23 11 12 21 22 syl3anc ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → M ⁡ X = M ⁡ q join ⁡ K r ↔ X = q join ⁡ K r
24 breq2 ⊢ X = q join ⁡ K r → P C X ↔ P C q join ⁡ K r
25 24 biimpd ⊢ X = q join ⁡ K r → P C X → P C q join ⁡ K r
26 11 adantr ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → K ∈ HL
27 simpll3 ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → P ∈ B
28 27 14 17 3jca ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → P ∈ B ∧ q ∈ A ∧ r ∈ A
29 28 adantr ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → P ∈ B ∧ q ∈ A ∧ r ∈ A
30 simplr ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → q ≠ r
31 simpr ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → P C q join ⁡ K r
32 1 8 2 3 cvrat2 ⊢ K ∈ HL ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → P ∈ A
33 26 29 30 31 32 syl112anc ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P C q join ⁡ K r → P ∈ A
34 33 ex ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → P C q join ⁡ K r → P ∈ A
35 25 34 syl9r ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → X = q join ⁡ K r → P C X → P ∈ A
36 23 35 sylbid ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r → M ⁡ X = M ⁡ q join ⁡ K r → P C X → P ∈ A
37 36 expimpd ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ q ∈ A ∧ r ∈ A → q ≠ r ∧ M ⁡ X = M ⁡ q join ⁡ K r → P C X → P ∈ A
38 37 rexlimdvva ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B → ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ M ⁡ X = M ⁡ q join ⁡ K r → P C X → P ∈ A
39 10 38 sylbid ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B → M ⁡ X ∈ N → P C X → P ∈ A
40 39 imp32 ⊢ K ∈ HL ∧ X ∈ B ∧ P ∈ B ∧ M ⁡ X ∈ N ∧ P C X → P ∈ A