Metamath Proof Explorer


Theorem lnoppinn0

Description: The segment between two points X and Y on opposite sides of a line D intersects D . (Contributed by Thierry Arnoux, 23-Aug-2026)

Ref Expression
Hypotheses lnoppinn0.p ⊢ P = Base G
lnoppinn0.i ⊢ I = Itv ⁡ G
lnoppinn0.l ⊢ L = Line 𝒢 ⁡ G
lnoppinn0.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
lnoppinn0.g ⊢ φ → G ∈ V
lnoppinn0.d ⊢ φ → D ∈ ran ⁡ L
lnoppinn0.x ⊢ φ → X ∈ P
lnoppinn0.y ⊢ φ → Y ∈ P
lnoppinn0.1 ⊢ φ → X O Y
Assertion lnoppinn0 ⊢ φ → D ∩ X I Y ≠ ∅

Proof

Step Hyp Ref Expression
1 lnoppinn0.p ⊢ P = Base G
2 lnoppinn0.i ⊢ I = Itv ⁡ G
3 lnoppinn0.l ⊢ L = Line 𝒢 ⁡ G
4 lnoppinn0.o ⊢ O = a b | a ∈ P ∖ D ∧ b ∈ P ∖ D ∧ ∃ t ∈ D t ∈ a I b
5 lnoppinn0.g ⊢ φ → G ∈ V
6 lnoppinn0.d ⊢ φ → D ∈ ran ⁡ L
7 lnoppinn0.x ⊢ φ → X ∈ P
8 lnoppinn0.y ⊢ φ → Y ∈ P
9 lnoppinn0.1 ⊢ φ → X O Y
10 simplr ⊢ φ ∧ t ∈ D ∧ t ∈ X I Y → t ∈ D
11 simpr ⊢ φ ∧ t ∈ D ∧ t ∈ X I Y → t ∈ X I Y
12 10 11 elind ⊢ φ ∧ t ∈ D ∧ t ∈ X I Y → t ∈ D ∩ X I Y
13 12 ne0d ⊢ φ ∧ t ∈ D ∧ t ∈ X I Y → D ∩ X I Y ≠ ∅
14 eqid ⊢ dist ⁡ G = dist ⁡ G
15 1 14 2 4 7 8 islnopp ⊢ φ → X O Y ↔ ¬ X ∈ D ∧ ¬ Y ∈ D ∧ ∃ t ∈ D t ∈ X I Y
16 9 15 mpbid ⊢ φ → ¬ X ∈ D ∧ ¬ Y ∈ D ∧ ∃ t ∈ D t ∈ X I Y
17 16 simprd ⊢ φ → ∃ t ∈ D t ∈ X I Y
18 13 17 r19.29a ⊢ φ → D ∩ X I Y ≠ ∅