Metamath Proof Explorer


Theorem lplnri3N

Description: Property of a lattice plane expressed as the join of 3 atoms. (Contributed by NM, 30-Jul-2012) (New usage is discouraged.)

Ref Expression
Hypotheses lplnri1.j ⊢ ∨ ˙ = join ⁡ K
lplnri1.a ⊢ A = Atoms ⁡ K
lplnri1.p ⊢ P = LPlanes ⁡ K
lplnri1.y ⊢ Y = Q ∨ ˙ R ∨ ˙ S
Assertion lplnri3N ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → R ≠ S

Proof

Step Hyp Ref Expression
1 lplnri1.j ⊢ ∨ ˙ = join ⁡ K
2 lplnri1.a ⊢ A = Atoms ⁡ K
3 lplnri1.p ⊢ P = LPlanes ⁡ K
4 lplnri1.y ⊢ Y = Q ∨ ˙ R ∨ ˙ S
5 simp1 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → K ∈ HL
6 simp22 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → R ∈ A
7 simp21 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → Q ∈ A
8 simp23 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → S ∈ A
9 eqid ⊢ ≤ K = ≤ K
10 9 1 2 3 4 lplnribN ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → ¬ R ≤ K Q ∨ ˙ S
11 9 1 2 atnlej2 ⊢ K ∈ HL ∧ R ∈ A ∧ Q ∈ A ∧ S ∈ A ∧ ¬ R ≤ K Q ∨ ˙ S → R ≠ S
12 5 6 7 8 10 11 syl131anc ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Y ∈ P → R ≠ S