Metamath Proof Explorer


Theorem lshpinN

Description: The intersection of two different hyperplanes is not a hyperplane. (Contributed by NM, 29-Oct-2014) (New usage is discouraged.)

Ref Expression
Hypotheses lshpin.h ⊢ H = LSHyp ⁡ W
lshpin.w ⊢ φ → W ∈ LVec
lshpin.t ⊢ φ → T ∈ H
lshpin.u ⊢ φ → U ∈ H
Assertion lshpinN ⊢ φ → T ∩ U ∈ H ↔ T = U

Proof

Step Hyp Ref Expression
1 lshpin.h ⊢ H = LSHyp ⁡ W
2 lshpin.w ⊢ φ → W ∈ LVec
3 lshpin.t ⊢ φ → T ∈ H
4 lshpin.u ⊢ φ → U ∈ H
5 inss1 ⊢ T ∩ U ⊆ T
6 2 adantr ⊢ φ ∧ T ∩ U ∈ H → W ∈ LVec
7 simpr ⊢ φ ∧ T ∩ U ∈ H → T ∩ U ∈ H
8 3 adantr ⊢ φ ∧ T ∩ U ∈ H → T ∈ H
9 1 6 7 8 lshpcmp ⊢ φ ∧ T ∩ U ∈ H → T ∩ U ⊆ T ↔ T ∩ U = T
10 5 9 mpbii ⊢ φ ∧ T ∩ U ∈ H → T ∩ U = T
11 inss2 ⊢ T ∩ U ⊆ U
12 4 adantr ⊢ φ ∧ T ∩ U ∈ H → U ∈ H
13 1 6 7 12 lshpcmp ⊢ φ ∧ T ∩ U ∈ H → T ∩ U ⊆ U ↔ T ∩ U = U
14 11 13 mpbii ⊢ φ ∧ T ∩ U ∈ H → T ∩ U = U
15 10 14 eqtr3d ⊢ φ ∧ T ∩ U ∈ H → T = U
16 15 ex ⊢ φ → T ∩ U ∈ H → T = U
17 inidm ⊢ T ∩ T = T
18 17 3 eqeltrid ⊢ φ → T ∩ T ∈ H
19 ineq2 ⊢ T = U → T ∩ T = T ∩ U
20 19 eleq1d ⊢ T = U → T ∩ T ∈ H ↔ T ∩ U ∈ H
21 18 20 syl5ibcom ⊢ φ → T = U → T ∩ U ∈ H
22 16 21 impbid ⊢ φ → T ∩ U ∈ H ↔ T = U