Metamath Proof Explorer


Theorem lshpkrlem2

Description: Lemma for lshpkrex . The value of tentative functional G is a scalar. (Contributed by NM, 16-Jul-2014)

Ref Expression
Hypotheses lshpkrlem.v ⊢ V = Base W
lshpkrlem.a ⊢ + ˙ = + W
lshpkrlem.n ⊢ N = LSpan ⁡ W
lshpkrlem.p ⊢ ⊕ ˙ = LSSum ⁡ W
lshpkrlem.h ⊢ H = LSHyp ⁡ W
lshpkrlem.w ⊢ φ → W ∈ LVec
lshpkrlem.u ⊢ φ → U ∈ H
lshpkrlem.z ⊢ φ → Z ∈ V
lshpkrlem.x ⊢ φ → X ∈ V
lshpkrlem.e ⊢ φ → U ⊕ ˙ N ⁡ Z = V
lshpkrlem.d ⊢ D = Scalar ⁡ W
lshpkrlem.k ⊢ K = Base D
lshpkrlem.t ⊢ · ˙ = ⋅ W
lshpkrlem.o ⊢ 0 ˙ = 0 D
lshpkrlem.g ⊢ G = x ∈ V ⟼ ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z
Assertion lshpkrlem2 ⊢ φ → G ⁡ X ∈ K

Proof

Step Hyp Ref Expression
1 lshpkrlem.v ⊢ V = Base W
2 lshpkrlem.a ⊢ + ˙ = + W
3 lshpkrlem.n ⊢ N = LSpan ⁡ W
4 lshpkrlem.p ⊢ ⊕ ˙ = LSSum ⁡ W
5 lshpkrlem.h ⊢ H = LSHyp ⁡ W
6 lshpkrlem.w ⊢ φ → W ∈ LVec
7 lshpkrlem.u ⊢ φ → U ∈ H
8 lshpkrlem.z ⊢ φ → Z ∈ V
9 lshpkrlem.x ⊢ φ → X ∈ V
10 lshpkrlem.e ⊢ φ → U ⊕ ˙ N ⁡ Z = V
11 lshpkrlem.d ⊢ D = Scalar ⁡ W
12 lshpkrlem.k ⊢ K = Base D
13 lshpkrlem.t ⊢ · ˙ = ⋅ W
14 lshpkrlem.o ⊢ 0 ˙ = 0 D
15 lshpkrlem.g ⊢ G = x ∈ V ⟼ ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z
16 eqeq1 ⊢ x = X → x = y + ˙ k · ˙ Z ↔ X = y + ˙ k · ˙ Z
17 16 rexbidv ⊢ x = X → ∃ y ∈ U x = y + ˙ k · ˙ Z ↔ ∃ y ∈ U X = y + ˙ k · ˙ Z
18 17 riotabidv ⊢ x = X → ι k ∈ K | ∃ y ∈ U x = y + ˙ k · ˙ Z = ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z
19 riotaex ⊢ ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z ∈ V
20 18 15 19 fvmpt ⊢ X ∈ V → G ⁡ X = ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z
21 9 20 syl ⊢ φ → G ⁡ X = ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z
22 1 2 3 4 5 6 7 8 9 10 11 12 13 lshpsmreu ⊢ φ → ∃! k ∈ K ∃ y ∈ U X = y + ˙ k · ˙ Z
23 riotacl ⊢ ∃! k ∈ K ∃ y ∈ U X = y + ˙ k · ˙ Z → ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z ∈ K
24 22 23 syl ⊢ φ → ι k ∈ K | ∃ y ∈ U X = y + ˙ k · ˙ Z ∈ K
25 21 24 eqeltrd ⊢ φ → G ⁡ X ∈ K