Metamath Proof Explorer
Description: A subspace member is a vector. (Contributed by NM, 11-Jan-2014)
(Revised by Mario Carneiro, 8-Jan-2015)
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Ref |
Expression |
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Hypotheses |
lssss.v |
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lssss.s |
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Assertion |
lssel |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
lssss.v |
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2 |
|
lssss.s |
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3 |
1 2
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lssss |
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4 |
3
|
sselda |
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