Metamath Proof Explorer


Theorem ltrncnvnid

Description: If a translation is different from the identity, so is its converse. (Contributed by NM, 17-Jun-2013)

Ref Expression
Hypotheses ltrn1o.b ⊢ B = Base K
ltrn1o.h ⊢ H = LHyp ⁡ K
ltrn1o.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion ltrncnvnid ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F -1 ≠ I ↾ B

Proof

Step Hyp Ref Expression
1 ltrn1o.b ⊢ B = Base K
2 ltrn1o.h ⊢ H = LHyp ⁡ K
3 ltrn1o.t ⊢ T = LTrn ⁡ K ⁡ W
4 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F ≠ I ↾ B
5 1 2 3 ltrn1o ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T → F : B ⟶ 1-1 onto B
6 5 3adant3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F : B ⟶ 1-1 onto B
7 f1orel ⊢ F : B ⟶ 1-1 onto B → Rel ⁡ F
8 6 7 syl ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → Rel ⁡ F
9 dfrel2 ⊢ Rel ⁡ F ↔ F -1 -1 = F
10 8 9 sylib ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F -1 -1 = F
11 cnveq ⊢ F -1 = I ↾ B → F -1 -1 = I ↾ B -1
12 10 11 sylan9req ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ F -1 = I ↾ B → F = I ↾ B -1
13 cnvresid ⊢ I ↾ B -1 = I ↾ B
14 12 13 eqtrdi ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B ∧ F -1 = I ↾ B → F = I ↾ B
15 14 ex ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F -1 = I ↾ B → F = I ↾ B
16 15 necon3d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F ≠ I ↾ B → F -1 ≠ I ↾ B
17 4 16 mpd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ F ≠ I ↾ B → F -1 ≠ I ↾ B