Metamath Proof Explorer


Theorem mapdh6b0N

Description: Lemmma for mapdh6N . (Contributed by NM, 23-Apr-2015) (New usage is discouraged.)

Ref Expression
Hypotheses mapdh.q ⊢ Q = 0 C
mapdh.i ⊢ I = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
mapdh.h ⊢ H = LHyp ⁡ K
mapdh.m ⊢ M = mapd ⁡ K ⁡ W
mapdh.u ⊢ U = DVecH ⁡ K ⁡ W
mapdh.v ⊢ V = Base U
mapdh.s ⊢ - ˙ = - U
mapdhc.o ⊢ 0 ˙ = 0 U
mapdh.n ⊢ N = LSpan ⁡ U
mapdh.c ⊢ C = LCDual ⁡ K ⁡ W
mapdh.d ⊢ D = Base C
mapdh.r ⊢ R = - C
mapdh.j ⊢ J = LSpan ⁡ C
mapdh.k ⊢ φ → K ∈ HL ∧ W ∈ H
mapdhc.f ⊢ φ → F ∈ D
mapdh.mn ⊢ φ → M ⁡ N ⁡ X = J ⁡ F
mapdhcl.x ⊢ φ → X ∈ V ∖ 0 ˙
mapdh.p ⊢ + ˙ = + U
mapdh.a ⊢ ✚ ˙ = + C
mapdh6b0.y ⊢ φ → Y ∈ V
mapdh6b0.z ⊢ φ → Z ∈ V
mapdh6b0.ne ⊢ φ → N ⁡ X ∩ N ⁡ Y Z = 0 ˙
Assertion mapdh6b0N ⊢ φ → ¬ X ∈ N ⁡ Y Z

Proof

Step Hyp Ref Expression
1 mapdh.q ⊢ Q = 0 C
2 mapdh.i ⊢ I = x ∈ V ⟼ if 2 nd ⁡ x = 0 ˙ Q ι h ∈ D | M ⁡ N ⁡ 2 nd ⁡ x = J ⁡ h ∧ M ⁡ N ⁡ 1 st ⁡ 1 st ⁡ x - ˙ 2 nd ⁡ x = J ⁡ 2 nd ⁡ 1 st ⁡ x R h
3 mapdh.h ⊢ H = LHyp ⁡ K
4 mapdh.m ⊢ M = mapd ⁡ K ⁡ W
5 mapdh.u ⊢ U = DVecH ⁡ K ⁡ W
6 mapdh.v ⊢ V = Base U
7 mapdh.s ⊢ - ˙ = - U
8 mapdhc.o ⊢ 0 ˙ = 0 U
9 mapdh.n ⊢ N = LSpan ⁡ U
10 mapdh.c ⊢ C = LCDual ⁡ K ⁡ W
11 mapdh.d ⊢ D = Base C
12 mapdh.r ⊢ R = - C
13 mapdh.j ⊢ J = LSpan ⁡ C
14 mapdh.k ⊢ φ → K ∈ HL ∧ W ∈ H
15 mapdhc.f ⊢ φ → F ∈ D
16 mapdh.mn ⊢ φ → M ⁡ N ⁡ X = J ⁡ F
17 mapdhcl.x ⊢ φ → X ∈ V ∖ 0 ˙
18 mapdh.p ⊢ + ˙ = + U
19 mapdh.a ⊢ ✚ ˙ = + C
20 mapdh6b0.y ⊢ φ → Y ∈ V
21 mapdh6b0.z ⊢ φ → Z ∈ V
22 mapdh6b0.ne ⊢ φ → N ⁡ X ∩ N ⁡ Y Z = 0 ˙
23 eqid ⊢ LSubSp ⁡ U = LSubSp ⁡ U
24 3 5 14 dvhlvec ⊢ φ → U ∈ LVec
25 3 5 14 dvhlmod ⊢ φ → U ∈ LMod
26 6 23 9 25 20 21 lspprcl ⊢ φ → N ⁡ Y Z ∈ LSubSp ⁡ U
27 6 8 9 23 24 26 17 lspdisjb ⊢ φ → ¬ X ∈ N ⁡ Y Z ↔ N ⁡ X ∩ N ⁡ Y Z = 0 ˙
28 22 27 mpbird ⊢ φ → ¬ X ∈ N ⁡ Y Z