Metamath Proof Explorer


Theorem matsca

Description: The matrix ring has the same scalars as its underlying linear structure. (Contributed by Stefan O'Rear, 4-Sep-2015) (Proof shortened by AV, 12-Nov-2024)

Ref Expression
Hypotheses matbas.a A = N Mat R
matbas.g G = R freeLMod N × N
Assertion matsca N Fin R V Scalar G = Scalar A

Proof

Step Hyp Ref Expression
1 matbas.a A = N Mat R
2 matbas.g G = R freeLMod N × N
3 scaid Scalar = Slot Scalar ndx
4 scandxnmulrndx Scalar ndx ndx
5 3 4 setsnid Scalar G = Scalar G sSet ndx R maMul N N N
6 eqid R maMul N N N = R maMul N N N
7 1 2 6 matval N Fin R V A = G sSet ndx R maMul N N N
8 7 fveq2d N Fin R V Scalar A = Scalar G sSet ndx R maMul N N N
9 5 8 eqtr4id N Fin R V Scalar G = Scalar A