Metamath Proof Explorer


Theorem matvsca

Description: The matrix ring has the same scalar multiplication as its underlying linear structure. (Contributed by Stefan O'Rear, 4-Sep-2015)

Ref Expression
Hypotheses matbas.a A = N Mat R
matbas.g G = R freeLMod N × N
Assertion matvsca N Fin R V G = A

Proof

Step Hyp Ref Expression
1 matbas.a A = N Mat R
2 matbas.g G = R freeLMod N × N
3 vscaid 𝑠 = Slot ndx
4 vscandx ndx = 6
5 3re 3
6 3lt6 3 < 6
7 5 6 gtneii 6 3
8 mulrndx ndx = 3
9 7 8 neeqtrri 6 ndx
10 4 9 eqnetri ndx ndx
11 3 10 setsnid G = G sSet ndx R maMul N N N
12 eqid R maMul N N N = R maMul N N N
13 1 2 12 matval N Fin R V A = G sSet ndx R maMul N N N
14 13 fveq2d N Fin R V A = G sSet ndx R maMul N N N
15 11 14 eqtr4id N Fin R V G = A