Metamath Proof Explorer


Theorem mavmul0g

Description: The result of the 0-dimensional multiplication of a matrix with a vector is always the empty set. (Contributed by AV, 1-Mar-2019)

Ref Expression
Hypothesis mavmul0.t ⊢ · ˙ = R maVecMul N N
Assertion mavmul0g ⊢ N = ∅ ∧ R ∈ V → X · ˙ Y = ∅

Proof

Step Hyp Ref Expression
1 mavmul0.t ⊢ · ˙ = R maVecMul N N
2 oveq12 ⊢ X = ∅ ∧ Y = ∅ → X · ˙ Y = ∅ · ˙ ∅
3 1 mavmul0 ⊢ N = ∅ ∧ R ∈ V → ∅ · ˙ ∅ = ∅
4 2 3 sylan9eq ⊢ X = ∅ ∧ Y = ∅ ∧ N = ∅ ∧ R ∈ V → X · ˙ Y = ∅
5 eqid ⊢ Base R = Base R
6 eqid ⊢ ⋅ R = ⋅ R
7 simpr ⊢ N = ∅ ∧ R ∈ V → R ∈ V
8 0fi ⊢ ∅ ∈ Fin
9 eleq1 ⊢ N = ∅ → N ∈ Fin ↔ ∅ ∈ Fin
10 8 9 mpbiri ⊢ N = ∅ → N ∈ Fin
11 10 adantr ⊢ N = ∅ ∧ R ∈ V → N ∈ Fin
12 1 5 6 7 11 11 mvmulfval ⊢ N = ∅ ∧ R ∈ V → · ˙ = i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l
13 12 dmeqd ⊢ N = ∅ ∧ R ∈ V → dom ⁡ · ˙ = dom ⁡ i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l
14 0ex ⊢ ∅ ∈ V
15 eleq1 ⊢ N = ∅ → N ∈ V ↔ ∅ ∈ V
16 14 15 mpbiri ⊢ N = ∅ → N ∈ V
17 16 mptexd ⊢ N = ∅ → k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l ∈ V
18 17 adantr ⊢ N = ∅ ∧ R ∈ V → k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l ∈ V
19 18 adantr ⊢ N = ∅ ∧ R ∈ V ∧ i ∈ Base R N × N ∧ j ∈ Base R N → k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l ∈ V
20 19 ralrimivva ⊢ N = ∅ ∧ R ∈ V → ∀ i ∈ Base R N × N ∀ j ∈ Base R N k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l ∈ V
21 eqid ⊢ i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l = i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l
22 21 dmmpoga ⊢ ∀ i ∈ Base R N × N ∀ j ∈ Base R N k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l ∈ V → dom ⁡ i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l = Base R N × N × Base R N
23 20 22 syl ⊢ N = ∅ ∧ R ∈ V → dom ⁡ i ∈ Base R N × N , j ∈ Base R N ⟼ k ∈ N ⟼ ∑ R l ∈ N k i l ⋅ R j ⁡ l = Base R N × N × Base R N
24 id ⊢ N = ∅ → N = ∅
25 24 24 xpeq12d ⊢ N = ∅ → N × N = ∅ × ∅
26 0xp ⊢ ∅ × ∅ = ∅
27 25 26 eqtrdi ⊢ N = ∅ → N × N = ∅
28 27 oveq2d ⊢ N = ∅ → Base R N × N = Base R ∅
29 fvex ⊢ Base R ∈ V
30 map0e ⊢ Base R ∈ V → Base R ∅ = 1 𝑜
31 29 30 mp1i ⊢ N = ∅ → Base R ∅ = 1 𝑜
32 28 31 eqtrd ⊢ N = ∅ → Base R N × N = 1 𝑜
33 32 adantr ⊢ N = ∅ ∧ R ∈ V → Base R N × N = 1 𝑜
34 df1o2 ⊢ 1 𝑜 = ∅
35 33 34 eqtrdi ⊢ N = ∅ ∧ R ∈ V → Base R N × N = ∅
36 oveq2 ⊢ N = ∅ → Base R N = Base R ∅
37 29 30 mp1i ⊢ R ∈ V → Base R ∅ = 1 𝑜
38 37 34 eqtrdi ⊢ R ∈ V → Base R ∅ = ∅
39 36 38 sylan9eq ⊢ N = ∅ ∧ R ∈ V → Base R N = ∅
40 35 39 xpeq12d ⊢ N = ∅ ∧ R ∈ V → Base R N × N × Base R N = ∅ × ∅
41 13 23 40 3eqtrd ⊢ N = ∅ ∧ R ∈ V → dom ⁡ · ˙ = ∅ × ∅
42 elsni ⊢ X ∈ ∅ → X = ∅
43 elsni ⊢ Y ∈ ∅ → Y = ∅
44 42 43 anim12i ⊢ X ∈ ∅ ∧ Y ∈ ∅ → X = ∅ ∧ Y = ∅
45 44 con3i ⊢ ¬ X = ∅ ∧ Y = ∅ → ¬ X ∈ ∅ ∧ Y ∈ ∅
46 ndmovg ⊢ dom ⁡ · ˙ = ∅ × ∅ ∧ ¬ X ∈ ∅ ∧ Y ∈ ∅ → X · ˙ Y = ∅
47 41 45 46 syl2anr ⊢ ¬ X = ∅ ∧ Y = ∅ ∧ N = ∅ ∧ R ∈ V → X · ˙ Y = ∅
48 4 47 pm2.61ian ⊢ N = ∅ ∧ R ∈ V → X · ˙ Y = ∅