Metamath Proof Explorer


Theorem mcubic

Description: Solutions to a monic cubic equation, a special case of cubic . (Contributed by Mario Carneiro, 24-Apr-2015)

Ref Expression
Hypotheses mcubic.b ⊢ φ → B ∈ ℂ
mcubic.c ⊢ φ → C ∈ ℂ
mcubic.d ⊢ φ → D ∈ ℂ
mcubic.x ⊢ φ → X ∈ ℂ
mcubic.t ⊢ φ → T ∈ ℂ
mcubic.3 ⊢ φ → T 3 = N + G 2
mcubic.g ⊢ φ → G ∈ ℂ
mcubic.2 ⊢ φ → G 2 = N 2 − 4 ⁢ M 3
mcubic.m ⊢ φ → M = B 2 − 3 ⁢ C
mcubic.n ⊢ φ → N = 2 ⁢ B 3 - 9 ⁢ B ⁢ C + 27 ⁢ D
mcubic.0 ⊢ φ → T ≠ 0
Assertion mcubic ⊢ φ → X 3 + B ⁢ X 2 + C ⁢ X + D = 0 ↔ ∃ r ∈ ℂ r 3 = 1 ∧ X = − B + r ⁢ T + M r ⁢ T 3

Proof

Step Hyp Ref Expression
1 mcubic.b ⊢ φ → B ∈ ℂ
2 mcubic.c ⊢ φ → C ∈ ℂ
3 mcubic.d ⊢ φ → D ∈ ℂ
4 mcubic.x ⊢ φ → X ∈ ℂ
5 mcubic.t ⊢ φ → T ∈ ℂ
6 mcubic.3 ⊢ φ → T 3 = N + G 2
7 mcubic.g ⊢ φ → G ∈ ℂ
8 mcubic.2 ⊢ φ → G 2 = N 2 − 4 ⁢ M 3
9 mcubic.m ⊢ φ → M = B 2 − 3 ⁢ C
10 mcubic.n ⊢ φ → N = 2 ⁢ B 3 - 9 ⁢ B ⁢ C + 27 ⁢ D
11 mcubic.0 ⊢ φ → T ≠ 0
12 1 sqcld ⊢ φ → B 2 ∈ ℂ
13 3cn ⊢ 3 ∈ ℂ
14 mulcl ⊢ 3 ∈ ℂ ∧ C ∈ ℂ → 3 ⁢ C ∈ ℂ
15 13 2 14 sylancr ⊢ φ → 3 ⁢ C ∈ ℂ
16 12 15 subcld ⊢ φ → B 2 − 3 ⁢ C ∈ ℂ
17 9 16 eqeltrd ⊢ φ → M ∈ ℂ
18 13 a1i ⊢ φ → 3 ∈ ℂ
19 3ne0 ⊢ 3 ≠ 0
20 19 a1i ⊢ φ → 3 ≠ 0
21 17 18 20 divcld ⊢ φ → M 3 ∈ ℂ
22 21 negcld ⊢ φ → − M 3 ∈ ℂ
23 2cn ⊢ 2 ∈ ℂ
24 3nn0 ⊢ 3 ∈ ℕ 0
25 expcl ⊢ B ∈ ℂ ∧ 3 ∈ ℕ 0 → B 3 ∈ ℂ
26 1 24 25 sylancl ⊢ φ → B 3 ∈ ℂ
27 mulcl ⊢ 2 ∈ ℂ ∧ B 3 ∈ ℂ → 2 ⁢ B 3 ∈ ℂ
28 23 26 27 sylancr ⊢ φ → 2 ⁢ B 3 ∈ ℂ
29 9cn ⊢ 9 ∈ ℂ
30 1 2 mulcld ⊢ φ → B ⁢ C ∈ ℂ
31 mulcl ⊢ 9 ∈ ℂ ∧ B ⁢ C ∈ ℂ → 9 ⁢ B ⁢ C ∈ ℂ
32 29 30 31 sylancr ⊢ φ → 9 ⁢ B ⁢ C ∈ ℂ
33 28 32 subcld ⊢ φ → 2 ⁢ B 3 − 9 ⁢ B ⁢ C ∈ ℂ
34 2nn0 ⊢ 2 ∈ ℕ 0
35 7nn ⊢ 7 ∈ ℕ
36 34 35 decnncl ⊢ 27 ∈ ℕ
37 36 nncni ⊢ 27 ∈ ℂ
38 mulcl ⊢ 27 ∈ ℂ ∧ D ∈ ℂ → 27 ⁢ D ∈ ℂ
39 37 3 38 sylancr ⊢ φ → 27 ⁢ D ∈ ℂ
40 33 39 addcld ⊢ φ → 2 ⁢ B 3 - 9 ⁢ B ⁢ C + 27 ⁢ D ∈ ℂ
41 10 40 eqeltrd ⊢ φ → N ∈ ℂ
42 37 a1i ⊢ φ → 27 ∈ ℂ
43 36 nnne0i ⊢ 27 ≠ 0
44 43 a1i ⊢ φ → 27 ≠ 0
45 41 42 44 divcld ⊢ φ → N 27 ∈ ℂ
46 1 18 20 divcld ⊢ φ → B 3 ∈ ℂ
47 4 46 addcld ⊢ φ → X + B 3 ∈ ℂ
48 5 18 20 divcld ⊢ φ → T 3 ∈ ℂ
49 48 negcld ⊢ φ → − T 3 ∈ ℂ
50 3nn ⊢ 3 ∈ ℕ
51 50 a1i ⊢ φ → 3 ∈ ℕ
52 n2dvds3 ⊢ ¬ 2 ∥ 3
53 52 a1i ⊢ φ → ¬ 2 ∥ 3
54 oexpneg ⊢ T 3 ∈ ℂ ∧ 3 ∈ ℕ ∧ ¬ 2 ∥ 3 → − T 3 3 = − T 3 3
55 48 51 53 54 syl3anc ⊢ φ → − T 3 3 = − T 3 3
56 24 a1i ⊢ φ → 3 ∈ ℕ 0
57 5 18 20 56 expdivd ⊢ φ → T 3 3 = T 3 3 3
58 3exp3 ⊢ 3 3 = 27
59 58 a1i ⊢ φ → 3 3 = 27
60 6 59 oveq12d ⊢ φ → T 3 3 3 = N + G 2 27
61 41 7 addcld ⊢ φ → N + G ∈ ℂ
62 2cnd ⊢ φ → 2 ∈ ℂ
63 2ne0 ⊢ 2 ≠ 0
64 63 a1i ⊢ φ → 2 ≠ 0
65 61 62 42 64 44 divdiv32d ⊢ φ → N + G 2 27 = N + G 27 2
66 41 7 addcomd ⊢ φ → N + G = G + N
67 66 oveq1d ⊢ φ → N + G 27 = G + N 27
68 7 41 42 44 divdird ⊢ φ → G + N 27 = G 27 + N 27
69 67 68 eqtrd ⊢ φ → N + G 27 = G 27 + N 27
70 69 oveq1d ⊢ φ → N + G 27 2 = G 27 + N 27 2
71 7 42 44 divcld ⊢ φ → G 27 ∈ ℂ
72 71 45 62 64 divdird ⊢ φ → G 27 + N 27 2 = G 27 2 + N 27 2
73 65 70 72 3eqtrd ⊢ φ → N + G 2 27 = G 27 2 + N 27 2
74 57 60 73 3eqtrd ⊢ φ → T 3 3 = G 27 2 + N 27 2
75 74 negeqd ⊢ φ → − T 3 3 = − G 27 2 + N 27 2
76 71 halfcld ⊢ φ → G 27 2 ∈ ℂ
77 45 halfcld ⊢ φ → N 27 2 ∈ ℂ
78 76 77 negdi2d ⊢ φ → − G 27 2 + N 27 2 = - G 27 2 - N 27 2
79 55 75 78 3eqtrd ⊢ φ → − T 3 3 = - G 27 2 - N 27 2
80 76 negcld ⊢ φ → − G 27 2 ∈ ℂ
81 sqneg ⊢ G 27 2 ∈ ℂ → − G 27 2 2 = G 27 2 2
82 76 81 syl ⊢ φ → − G 27 2 2 = G 27 2 2
83 71 62 64 sqdivd ⊢ φ → G 27 2 2 = G 27 2 2 2
84 45 62 64 sqdivd ⊢ φ → N 27 2 2 = N 27 2 2 2
85 41 42 44 sqdivd ⊢ φ → N 27 2 = N 2 27 2
86 85 oveq1d ⊢ φ → N 27 2 2 2 = N 2 27 2 2 2
87 84 86 eqtr2d ⊢ φ → N 2 27 2 2 2 = N 27 2 2
88 4cn ⊢ 4 ∈ ℂ
89 88 a1i ⊢ φ → 4 ∈ ℂ
90 expcl ⊢ M ∈ ℂ ∧ 3 ∈ ℕ 0 → M 3 ∈ ℂ
91 17 24 90 sylancl ⊢ φ → M 3 ∈ ℂ
92 37 sqcli ⊢ 27 2 ∈ ℂ
93 92 a1i ⊢ φ → 27 2 ∈ ℂ
94 sqne0 ⊢ 27 ∈ ℂ → 27 2 ≠ 0 ↔ 27 ≠ 0
95 42 94 syl ⊢ φ → 27 2 ≠ 0 ↔ 27 ≠ 0
96 44 95 mpbird ⊢ φ → 27 2 ≠ 0
97 89 91 93 96 divassd ⊢ φ → 4 ⁢ M 3 27 2 = 4 ⁢ M 3 27 2
98 29 a1i ⊢ φ → 9 ∈ ℂ
99 9nn ⊢ 9 ∈ ℕ
100 99 nnne0i ⊢ 9 ≠ 0
101 100 a1i ⊢ φ → 9 ≠ 0
102 17 98 101 56 expdivd ⊢ φ → M 9 3 = M 3 9 3
103 23 13 mulcomi ⊢ 2 ⋅ 3 = 3 ⋅ 2
104 103 oveq2i ⊢ 3 2 ⋅ 3 = 3 3 ⋅ 2
105 expmul ⊢ 3 ∈ ℂ ∧ 2 ∈ ℕ 0 ∧ 3 ∈ ℕ 0 → 3 2 ⋅ 3 = 3 2 3
106 13 34 24 105 mp3an ⊢ 3 2 ⋅ 3 = 3 2 3
107 expmul ⊢ 3 ∈ ℂ ∧ 3 ∈ ℕ 0 ∧ 2 ∈ ℕ 0 → 3 3 ⋅ 2 = 3 3 2
108 13 24 34 107 mp3an ⊢ 3 3 ⋅ 2 = 3 3 2
109 104 106 108 3eqtr3i ⊢ 3 2 3 = 3 3 2
110 sq3 ⊢ 3 2 = 9
111 110 oveq1i ⊢ 3 2 3 = 9 3
112 58 oveq1i ⊢ 3 3 2 = 27 2
113 109 111 112 3eqtr3i ⊢ 9 3 = 27 2
114 113 oveq2i ⊢ M 3 9 3 = M 3 27 2
115 102 114 eqtrdi ⊢ φ → M 9 3 = M 3 27 2
116 115 oveq2d ⊢ φ → 4 ⁢ M 9 3 = 4 ⁢ M 3 27 2
117 97 116 eqtr4d ⊢ φ → 4 ⁢ M 3 27 2 = 4 ⁢ M 9 3
118 117 oveq1d ⊢ φ → 4 ⁢ M 3 27 2 2 2 = 4 ⁢ M 9 3 2 2
119 sq2 ⊢ 2 2 = 4
120 119 oveq2i ⊢ 4 ⁢ M 9 3 2 2 = 4 ⁢ M 9 3 4
121 17 98 101 divcld ⊢ φ → M 9 ∈ ℂ
122 expcl ⊢ M 9 ∈ ℂ ∧ 3 ∈ ℕ 0 → M 9 3 ∈ ℂ
123 121 24 122 sylancl ⊢ φ → M 9 3 ∈ ℂ
124 4ne0 ⊢ 4 ≠ 0
125 124 a1i ⊢ φ → 4 ≠ 0
126 123 89 125 divcan3d ⊢ φ → 4 ⁢ M 9 3 4 = M 9 3
127 120 126 eqtrid ⊢ φ → 4 ⁢ M 9 3 2 2 = M 9 3
128 118 127 eqtrd ⊢ φ → 4 ⁢ M 3 27 2 2 2 = M 9 3
129 87 128 oveq12d ⊢ φ → N 2 27 2 2 2 − 4 ⁢ M 3 27 2 2 2 = N 27 2 2 − M 9 3
130 41 sqcld ⊢ φ → N 2 ∈ ℂ
131 130 93 96 divcld ⊢ φ → N 2 27 2 ∈ ℂ
132 mulcl ⊢ 4 ∈ ℂ ∧ M 3 ∈ ℂ → 4 ⁢ M 3 ∈ ℂ
133 88 91 132 sylancr ⊢ φ → 4 ⁢ M 3 ∈ ℂ
134 133 93 96 divcld ⊢ φ → 4 ⁢ M 3 27 2 ∈ ℂ
135 23 sqcli ⊢ 2 2 ∈ ℂ
136 135 a1i ⊢ φ → 2 2 ∈ ℂ
137 119 124 eqnetri ⊢ 2 2 ≠ 0
138 137 a1i ⊢ φ → 2 2 ≠ 0
139 131 134 136 138 divsubdird ⊢ φ → N 2 27 2 − 4 ⁢ M 3 27 2 2 2 = N 2 27 2 2 2 − 4 ⁢ M 3 27 2 2 2
140 77 sqcld ⊢ φ → N 27 2 2 ∈ ℂ
141 140 123 negsubd ⊢ φ → N 27 2 2 + − M 9 3 = N 27 2 2 − M 9 3
142 129 139 141 3eqtr4d ⊢ φ → N 2 27 2 − 4 ⁢ M 3 27 2 2 2 = N 27 2 2 + − M 9 3
143 7 42 44 sqdivd ⊢ φ → G 27 2 = G 2 27 2
144 8 oveq1d ⊢ φ → G 2 27 2 = N 2 − 4 ⁢ M 3 27 2
145 130 133 93 96 divsubdird ⊢ φ → N 2 − 4 ⁢ M 3 27 2 = N 2 27 2 − 4 ⁢ M 3 27 2
146 143 144 145 3eqtrd ⊢ φ → G 27 2 = N 2 27 2 − 4 ⁢ M 3 27 2
147 146 oveq1d ⊢ φ → G 27 2 2 2 = N 2 27 2 − 4 ⁢ M 3 27 2 2 2
148 oexpneg ⊢ M 9 ∈ ℂ ∧ 3 ∈ ℕ ∧ ¬ 2 ∥ 3 → − M 9 3 = − M 9 3
149 121 51 53 148 syl3anc ⊢ φ → − M 9 3 = − M 9 3
150 149 oveq2d ⊢ φ → N 27 2 2 + − M 9 3 = N 27 2 2 + − M 9 3
151 142 147 150 3eqtr4d ⊢ φ → G 27 2 2 2 = N 27 2 2 + − M 9 3
152 82 83 151 3eqtrd ⊢ φ → − G 27 2 2 = N 27 2 2 + − M 9 3
153 17 18 18 20 20 divdiv1d ⊢ φ → M 3 3 = M 3 ⋅ 3
154 3t3e9 ⊢ 3 ⋅ 3 = 9
155 154 oveq2i ⊢ M 3 ⋅ 3 = M 9
156 153 155 eqtrdi ⊢ φ → M 3 3 = M 9
157 156 negeqd ⊢ φ → − M 3 3 = − M 9
158 21 18 20 divnegd ⊢ φ → − M 3 3 = − M 3 3
159 157 158 eqtr3d ⊢ φ → − M 9 = − M 3 3
160 eqidd ⊢ φ → N 27 2 = N 27 2
161 5 18 11 20 divne0d ⊢ φ → T 3 ≠ 0
162 48 161 negne0d ⊢ φ → − T 3 ≠ 0
163 22 45 47 49 79 80 152 159 160 162 dcubic ⊢ φ → X + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = 0 ↔ ∃ r ∈ ℂ r 3 = 1 ∧ X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3
164 binom3 ⊢ X ∈ ℂ ∧ B 3 ∈ ℂ → X + B 3 3 = X 3 + 3 ⁢ X 2 ⁢ B 3 + 3 ⁢ X ⁢ B 3 2 + B 3 3
165 4 46 164 syl2anc ⊢ φ → X + B 3 3 = X 3 + 3 ⁢ X 2 ⁢ B 3 + 3 ⁢ X ⁢ B 3 2 + B 3 3
166 4 sqcld ⊢ φ → X 2 ∈ ℂ
167 18 166 46 mul12d ⊢ φ → 3 ⁢ X 2 ⁢ B 3 = X 2 ⁢ 3 ⁢ B 3
168 1 18 20 divcan2d ⊢ φ → 3 ⁢ B 3 = B
169 168 oveq2d ⊢ φ → X 2 ⁢ 3 ⁢ B 3 = X 2 ⁢ B
170 166 1 mulcomd ⊢ φ → X 2 ⁢ B = B ⁢ X 2
171 167 169 170 3eqtrd ⊢ φ → 3 ⁢ X 2 ⁢ B 3 = B ⁢ X 2
172 171 oveq2d ⊢ φ → X 3 + 3 ⁢ X 2 ⁢ B 3 = X 3 + B ⁢ X 2
173 172 oveq1d ⊢ φ → X 3 + 3 ⁢ X 2 ⁢ B 3 + 3 ⁢ X ⁢ B 3 2 + B 3 3 = X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3
174 165 173 eqtrd ⊢ φ → X + B 3 3 = X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3
175 174 oveq1d ⊢ φ → X + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27
176 expcl ⊢ X ∈ ℂ ∧ 3 ∈ ℕ 0 → X 3 ∈ ℂ
177 4 24 176 sylancl ⊢ φ → X 3 ∈ ℂ
178 1 166 mulcld ⊢ φ → B ⁢ X 2 ∈ ℂ
179 177 178 addcld ⊢ φ → X 3 + B ⁢ X 2 ∈ ℂ
180 46 sqcld ⊢ φ → B 3 2 ∈ ℂ
181 4 180 mulcld ⊢ φ → X ⁢ B 3 2 ∈ ℂ
182 18 181 mulcld ⊢ φ → 3 ⁢ X ⁢ B 3 2 ∈ ℂ
183 expcl ⊢ B 3 ∈ ℂ ∧ 3 ∈ ℕ 0 → B 3 3 ∈ ℂ
184 46 24 183 sylancl ⊢ φ → B 3 3 ∈ ℂ
185 182 184 addcld ⊢ φ → 3 ⁢ X ⁢ B 3 2 + B 3 3 ∈ ℂ
186 22 47 mulcld ⊢ φ → − M 3 ⁢ X + B 3 ∈ ℂ
187 186 45 addcld ⊢ φ → − M 3 ⁢ X + B 3 + N 27 ∈ ℂ
188 179 185 187 addassd ⊢ φ → X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27
189 22 4 46 adddid ⊢ φ → − M 3 ⁢ X + B 3 = − M 3 ⁢ X + − M 3 ⁢ B 3
190 189 oveq1d ⊢ φ → − M 3 ⁢ X + B 3 + N 27 = − M 3 ⁢ X + − M 3 ⁢ B 3 + N 27
191 22 4 mulcld ⊢ φ → − M 3 ⁢ X ∈ ℂ
192 22 46 mulcld ⊢ φ → − M 3 ⁢ B 3 ∈ ℂ
193 191 192 45 addassd ⊢ φ → − M 3 ⁢ X + − M 3 ⁢ B 3 + N 27 = − M 3 ⁢ X + − M 3 ⁢ B 3 + N 27
194 9 oveq1d ⊢ φ → M 3 = B 2 − 3 ⁢ C 3
195 12 15 18 20 divsubdird ⊢ φ → B 2 − 3 ⁢ C 3 = B 2 3 − 3 ⁢ C 3
196 2 18 20 divcan3d ⊢ φ → 3 ⁢ C 3 = C
197 196 oveq2d ⊢ φ → B 2 3 − 3 ⁢ C 3 = B 2 3 − C
198 194 195 197 3eqtrd ⊢ φ → M 3 = B 2 3 − C
199 198 negeqd ⊢ φ → − M 3 = − B 2 3 − C
200 12 18 20 divcld ⊢ φ → B 2 3 ∈ ℂ
201 200 2 negsubdi2d ⊢ φ → − B 2 3 − C = C − B 2 3
202 199 201 eqtrd ⊢ φ → − M 3 = C − B 2 3
203 202 oveq1d ⊢ φ → − M 3 ⁢ X = C − B 2 3 ⁢ X
204 2 200 4 subdird ⊢ φ → C − B 2 3 ⁢ X = C ⁢ X − B 2 3 ⁢ X
205 200 4 mulcomd ⊢ φ → B 2 3 ⁢ X = X ⁢ B 2 3
206 13 sqvali ⊢ 3 2 = 3 ⋅ 3
207 206 oveq2i ⊢ B 2 3 2 = B 2 3 ⋅ 3
208 1 18 20 sqdivd ⊢ φ → B 3 2 = B 2 3 2
209 12 18 18 20 20 divdiv1d ⊢ φ → B 2 3 3 = B 2 3 ⋅ 3
210 207 208 209 3eqtr4a ⊢ φ → B 3 2 = B 2 3 3
211 210 oveq2d ⊢ φ → 3 ⁢ B 3 2 = 3 ⁢ B 2 3 3
212 200 18 20 divcan2d ⊢ φ → 3 ⁢ B 2 3 3 = B 2 3
213 211 212 eqtrd ⊢ φ → 3 ⁢ B 3 2 = B 2 3
214 213 oveq2d ⊢ φ → X ⁢ 3 ⁢ B 3 2 = X ⁢ B 2 3
215 4 18 180 mul12d ⊢ φ → X ⁢ 3 ⁢ B 3 2 = 3 ⁢ X ⁢ B 3 2
216 205 214 215 3eqtr2d ⊢ φ → B 2 3 ⁢ X = 3 ⁢ X ⁢ B 3 2
217 216 oveq2d ⊢ φ → C ⁢ X − B 2 3 ⁢ X = C ⁢ X − 3 ⁢ X ⁢ B 3 2
218 203 204 217 3eqtrd ⊢ φ → − M 3 ⁢ X = C ⁢ X − 3 ⁢ X ⁢ B 3 2
219 202 oveq1d ⊢ φ → − M 3 ⁢ B 3 = C − B 2 3 ⁢ B 3
220 2 200 46 subdird ⊢ φ → C − B 2 3 ⁢ B 3 = C ⁢ B 3 − B 2 3 ⁢ B 3
221 2 1 18 20 divassd ⊢ φ → C ⁢ B 3 = C ⁢ B 3
222 2 1 mulcomd ⊢ φ → C ⁢ B = B ⁢ C
223 222 oveq1d ⊢ φ → C ⁢ B 3 = B ⁢ C 3
224 221 223 eqtr3d ⊢ φ → C ⁢ B 3 = B ⁢ C 3
225 12 18 1 18 20 20 divmuldivd ⊢ φ → B 2 3 ⁢ B 3 = B 2 ⁢ B 3 ⋅ 3
226 df-3 ⊢ 3 = 2 + 1
227 226 oveq2i ⊢ B 3 = B 2 + 1
228 expp1 ⊢ B ∈ ℂ ∧ 2 ∈ ℕ 0 → B 2 + 1 = B 2 ⁢ B
229 1 34 228 sylancl ⊢ φ → B 2 + 1 = B 2 ⁢ B
230 227 229 eqtr2id ⊢ φ → B 2 ⁢ B = B 3
231 154 a1i ⊢ φ → 3 ⋅ 3 = 9
232 230 231 oveq12d ⊢ φ → B 2 ⁢ B 3 ⋅ 3 = B 3 9
233 225 232 eqtrd ⊢ φ → B 2 3 ⁢ B 3 = B 3 9
234 224 233 oveq12d ⊢ φ → C ⁢ B 3 − B 2 3 ⁢ B 3 = B ⁢ C 3 − B 3 9
235 219 220 234 3eqtrd ⊢ φ → − M 3 ⁢ B 3 = B ⁢ C 3 − B 3 9
236 10 oveq1d ⊢ φ → N 27 = 2 ⁢ B 3 - 9 ⁢ B ⁢ C + 27 ⁢ D 27
237 33 39 42 44 divdird ⊢ φ → 2 ⁢ B 3 - 9 ⁢ B ⁢ C + 27 ⁢ D 27 = 2 ⁢ B 3 − 9 ⁢ B ⁢ C 27 + 27 ⁢ D 27
238 28 32 42 44 divsubdird ⊢ φ → 2 ⁢ B 3 − 9 ⁢ B ⁢ C 27 = 2 ⁢ B 3 27 − 9 ⁢ B ⁢ C 27
239 9t3e27 ⊢ 9 ⋅ 3 = 27
240 239 oveq2i ⊢ 9 ⁢ B ⁢ C 9 ⋅ 3 = 9 ⁢ B ⁢ C 27
241 30 18 98 20 101 divcan5d ⊢ φ → 9 ⁢ B ⁢ C 9 ⋅ 3 = B ⁢ C 3
242 240 241 eqtr3id ⊢ φ → 9 ⁢ B ⁢ C 27 = B ⁢ C 3
243 242 oveq2d ⊢ φ → 2 ⁢ B 3 27 − 9 ⁢ B ⁢ C 27 = 2 ⁢ B 3 27 − B ⁢ C 3
244 238 243 eqtrd ⊢ φ → 2 ⁢ B 3 − 9 ⁢ B ⁢ C 27 = 2 ⁢ B 3 27 − B ⁢ C 3
245 3 42 44 divcan3d ⊢ φ → 27 ⁢ D 27 = D
246 244 245 oveq12d ⊢ φ → 2 ⁢ B 3 − 9 ⁢ B ⁢ C 27 + 27 ⁢ D 27 = 2 ⁢ B 3 27 - B ⁢ C 3 + D
247 236 237 246 3eqtrd ⊢ φ → N 27 = 2 ⁢ B 3 27 - B ⁢ C 3 + D
248 235 247 oveq12d ⊢ φ → − M 3 ⁢ B 3 + N 27 = B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 − B ⁢ C 3 + D
249 26 98 101 divcld ⊢ φ → B 3 9 ∈ ℂ
250 28 42 44 divcld ⊢ φ → 2 ⁢ B 3 27 ∈ ℂ
251 249 250 negsubdi2d ⊢ φ → − B 3 9 − 2 ⁢ B 3 27 = 2 ⁢ B 3 27 − B 3 9
252 1 18 20 56 expdivd ⊢ φ → B 3 3 = B 3 3 3
253 58 oveq2i ⊢ B 3 3 3 = B 3 27
254 ax-1cn ⊢ 1 ∈ ℂ
255 2p1e3 ⊢ 2 + 1 = 3
256 13 23 254 255 subaddrii ⊢ 3 − 2 = 1
257 256 oveq1i ⊢ 3 − 2 ⁢ B 3 = 1 ⁢ B 3
258 26 mullidd ⊢ φ → 1 ⁢ B 3 = B 3
259 257 258 eqtrid ⊢ φ → 3 − 2 ⁢ B 3 = B 3
260 18 62 26 subdird ⊢ φ → 3 − 2 ⁢ B 3 = 3 ⁢ B 3 − 2 ⁢ B 3
261 259 260 eqtr3d ⊢ φ → B 3 = 3 ⁢ B 3 − 2 ⁢ B 3
262 261 oveq1d ⊢ φ → B 3 27 = 3 ⁢ B 3 − 2 ⁢ B 3 27
263 mulcl ⊢ 3 ∈ ℂ ∧ B 3 ∈ ℂ → 3 ⁢ B 3 ∈ ℂ
264 13 26 263 sylancr ⊢ φ → 3 ⁢ B 3 ∈ ℂ
265 264 28 42 44 divsubdird ⊢ φ → 3 ⁢ B 3 − 2 ⁢ B 3 27 = 3 ⁢ B 3 27 − 2 ⁢ B 3 27
266 262 265 eqtrd ⊢ φ → B 3 27 = 3 ⁢ B 3 27 − 2 ⁢ B 3 27
267 253 266 eqtrid ⊢ φ → B 3 3 3 = 3 ⁢ B 3 27 − 2 ⁢ B 3 27
268 29 13 239 mulcomli ⊢ 3 ⋅ 9 = 27
269 268 oveq2i ⊢ 3 ⁢ B 3 3 ⋅ 9 = 3 ⁢ B 3 27
270 26 98 18 101 20 divcan5d ⊢ φ → 3 ⁢ B 3 3 ⋅ 9 = B 3 9
271 269 270 eqtr3id ⊢ φ → 3 ⁢ B 3 27 = B 3 9
272 271 oveq1d ⊢ φ → 3 ⁢ B 3 27 − 2 ⁢ B 3 27 = B 3 9 − 2 ⁢ B 3 27
273 252 267 272 3eqtrd ⊢ φ → B 3 3 = B 3 9 − 2 ⁢ B 3 27
274 273 negeqd ⊢ φ → − B 3 3 = − B 3 9 − 2 ⁢ B 3 27
275 30 18 20 divcld ⊢ φ → B ⁢ C 3 ∈ ℂ
276 275 249 250 npncan3d ⊢ φ → B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 - B ⁢ C 3 = 2 ⁢ B 3 27 − B 3 9
277 251 274 276 3eqtr4d ⊢ φ → − B 3 3 = B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 - B ⁢ C 3
278 277 oveq1d ⊢ φ → - B 3 3 + D = B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 − B ⁢ C 3 + D
279 184 negcld ⊢ φ → − B 3 3 ∈ ℂ
280 279 3 addcomd ⊢ φ → - B 3 3 + D = D + − B 3 3
281 235 192 eqeltrrd ⊢ φ → B ⁢ C 3 − B 3 9 ∈ ℂ
282 250 275 subcld ⊢ φ → 2 ⁢ B 3 27 − B ⁢ C 3 ∈ ℂ
283 281 282 3 addassd ⊢ φ → B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 − B ⁢ C 3 + D = B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 − B ⁢ C 3 + D
284 278 280 283 3eqtr3d ⊢ φ → D + − B 3 3 = B ⁢ C 3 − B 3 9 + 2 ⁢ B 3 27 − B ⁢ C 3 + D
285 3 184 negsubd ⊢ φ → D + − B 3 3 = D − B 3 3
286 248 284 285 3eqtr2d ⊢ φ → − M 3 ⁢ B 3 + N 27 = D − B 3 3
287 218 286 oveq12d ⊢ φ → − M 3 ⁢ X + − M 3 ⁢ B 3 + N 27 = C ⁢ X − 3 ⁢ X ⁢ B 3 2 + D - B 3 3
288 190 193 287 3eqtrd ⊢ φ → − M 3 ⁢ X + B 3 + N 27 = C ⁢ X − 3 ⁢ X ⁢ B 3 2 + D - B 3 3
289 2 4 mulcld ⊢ φ → C ⁢ X ∈ ℂ
290 289 3 182 184 addsub4d ⊢ φ → C ⁢ X + D - 3 ⁢ X ⁢ B 3 2 + B 3 3 = C ⁢ X − 3 ⁢ X ⁢ B 3 2 + D - B 3 3
291 288 290 eqtr4d ⊢ φ → − M 3 ⁢ X + B 3 + N 27 = C ⁢ X + D - 3 ⁢ X ⁢ B 3 2 + B 3 3
292 291 oveq2d ⊢ φ → 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = 3 ⁢ X ⁢ B 3 2 + B 3 3 + C ⁢ X + D - 3 ⁢ X ⁢ B 3 2 + B 3 3
293 289 3 addcld ⊢ φ → C ⁢ X + D ∈ ℂ
294 185 293 pncan3d ⊢ φ → 3 ⁢ X ⁢ B 3 2 + B 3 3 + C ⁢ X + D - 3 ⁢ X ⁢ B 3 2 + B 3 3 = C ⁢ X + D
295 292 294 eqtrd ⊢ φ → 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = C ⁢ X + D
296 295 oveq2d ⊢ φ → X 3 + B ⁢ X 2 + 3 ⁢ X ⁢ B 3 2 + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = X 3 + B ⁢ X 2 + C ⁢ X + D
297 175 188 296 3eqtrd ⊢ φ → X + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = X 3 + B ⁢ X 2 + C ⁢ X + D
298 297 eqeq1d ⊢ φ → X + B 3 3 + − M 3 ⁢ X + B 3 + N 27 = 0 ↔ X 3 + B ⁢ X 2 + C ⁢ X + D = 0
299 oveq1 ⊢ r = 0 → r 3 = 0 3
300 0exp ⊢ 3 ∈ ℕ → 0 3 = 0
301 50 300 ax-mp ⊢ 0 3 = 0
302 299 301 eqtrdi ⊢ r = 0 → r 3 = 0
303 0ne1 ⊢ 0 ≠ 1
304 303 a1i ⊢ r = 0 → 0 ≠ 1
305 302 304 eqnetrd ⊢ r = 0 → r 3 ≠ 1
306 305 necon2i ⊢ r 3 = 1 → r ≠ 0
307 eqcom ⊢ X = − B + r ⁢ T + M r ⁢ T 3 ↔ − B + r ⁢ T + M r ⁢ T 3 = X
308 1 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B ∈ ℂ
309 simprl ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ∈ ℂ
310 5 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → T ∈ ℂ
311 309 310 mulcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T ∈ ℂ
312 17 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M ∈ ℂ
313 simprr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ≠ 0
314 11 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → T ≠ 0
315 309 310 313 314 mulne0d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T ≠ 0
316 312 311 315 divcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M r ⁢ T ∈ ℂ
317 311 316 addcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T + M r ⁢ T ∈ ℂ
318 13 a1i ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → 3 ∈ ℂ
319 19 a1i ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → 3 ≠ 0
320 308 317 318 319 divdird ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B + r ⁢ T + M r ⁢ T 3 = B 3 + r ⁢ T + M r ⁢ T 3
321 308 311 316 addassd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B + r ⁢ T + M r ⁢ T = B + r ⁢ T + M r ⁢ T
322 321 oveq1d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B + r ⁢ T + M r ⁢ T 3 = B + r ⁢ T + M r ⁢ T 3
323 46 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B 3 ∈ ℂ
324 317 318 319 divcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T + M r ⁢ T 3 ∈ ℂ
325 323 324 subnegd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B 3 − − r ⁢ T + M r ⁢ T 3 = B 3 + r ⁢ T + M r ⁢ T 3
326 320 322 325 3eqtr4d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → B + r ⁢ T + M r ⁢ T 3 = B 3 − − r ⁢ T + M r ⁢ T 3
327 326 negeqd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − B + r ⁢ T + M r ⁢ T 3 = − B 3 − − r ⁢ T + M r ⁢ T 3
328 324 negcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T + M r ⁢ T 3 ∈ ℂ
329 323 328 negsubdi2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − B 3 − − r ⁢ T + M r ⁢ T 3 = - r ⁢ T + M r ⁢ T 3 - B 3
330 327 329 eqtrd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − B + r ⁢ T + M r ⁢ T 3 = - r ⁢ T + M r ⁢ T 3 - B 3
331 330 eqeq1d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − B + r ⁢ T + M r ⁢ T 3 = X ↔ - r ⁢ T + M r ⁢ T 3 - B 3 = X
332 307 331 bitrid ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → X = − B + r ⁢ T + M r ⁢ T 3 ↔ - r ⁢ T + M r ⁢ T 3 - B 3 = X
333 4 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → X ∈ ℂ
334 328 323 333 subadd2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → - r ⁢ T + M r ⁢ T 3 - B 3 = X ↔ X + B 3 = − r ⁢ T + M r ⁢ T 3
335 311 316 318 319 divdird ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T + M r ⁢ T 3 = r ⁢ T 3 + M r ⁢ T 3
336 335 negeqd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T + M r ⁢ T 3 = − r ⁢ T 3 + M r ⁢ T 3
337 311 318 319 divcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T 3 ∈ ℂ
338 316 318 319 divcld ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M r ⁢ T 3 ∈ ℂ
339 337 338 negdi2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T 3 + M r ⁢ T 3 = - r ⁢ T 3 - M r ⁢ T 3
340 309 310 318 319 divassd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T 3 = r ⁢ T 3
341 340 negeqd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T 3 = − r ⁢ T 3
342 48 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → T 3 ∈ ℂ
343 309 342 mulneg2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ − T 3 = − r ⁢ T 3
344 341 343 eqtr4d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T 3 = r ⁢ − T 3
345 312 311 318 315 319 divdiv32d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M r ⁢ T 3 = M 3 r ⁢ T
346 21 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M 3 ∈ ℂ
347 346 311 318 315 319 divcan7d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M 3 3 r ⁢ T 3 = M 3 r ⁢ T
348 156 oveq1d ⊢ φ → M 3 3 r ⁢ T 3 = M 9 r ⁢ T 3
349 348 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M 3 3 r ⁢ T 3 = M 9 r ⁢ T 3
350 345 347 349 3eqtr2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M r ⁢ T 3 = M 9 r ⁢ T 3
351 121 adantr ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M 9 ∈ ℂ
352 311 318 315 319 divne0d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → r ⁢ T 3 ≠ 0
353 351 337 352 div2negd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − M 9 − r ⁢ T 3 = M 9 r ⁢ T 3
354 344 oveq2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − M 9 − r ⁢ T 3 = − M 9 r ⁢ − T 3
355 350 353 354 3eqtr2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → M r ⁢ T 3 = − M 9 r ⁢ − T 3
356 344 355 oveq12d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → - r ⁢ T 3 - M r ⁢ T 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3
357 336 339 356 3eqtrd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → − r ⁢ T + M r ⁢ T 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3
358 357 eqeq2d ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → X + B 3 = − r ⁢ T + M r ⁢ T 3 ↔ X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3
359 332 334 358 3bitrrd ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3 ↔ X = − B + r ⁢ T + M r ⁢ T 3
360 359 anassrs ⊢ φ ∧ r ∈ ℂ ∧ r ≠ 0 → X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3 ↔ X = − B + r ⁢ T + M r ⁢ T 3
361 306 360 sylan2 ⊢ φ ∧ r ∈ ℂ ∧ r 3 = 1 → X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3 ↔ X = − B + r ⁢ T + M r ⁢ T 3
362 361 pm5.32da ⊢ φ ∧ r ∈ ℂ → r 3 = 1 ∧ X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3 ↔ r 3 = 1 ∧ X = − B + r ⁢ T + M r ⁢ T 3
363 362 rexbidva ⊢ φ → ∃ r ∈ ℂ r 3 = 1 ∧ X + B 3 = r ⁢ − T 3 − − M 9 r ⁢ − T 3 ↔ ∃ r ∈ ℂ r 3 = 1 ∧ X = − B + r ⁢ T + M r ⁢ T 3
364 163 298 363 3bitr3d ⊢ φ → X 3 + B ⁢ X 2 + C ⁢ X + D = 0 ↔ ∃ r ∈ ℂ r 3 = 1 ∧ X = − B + r ⁢ T + M r ⁢ T 3