Metamath Proof Explorer


Theorem mdandyvrx7

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx7.1 ⊢ φ ⊻ ζ
mdandyvrx7.2 ⊢ ψ ⊻ σ
mdandyvrx7.3 ⊢ χ ↔ ψ
mdandyvrx7.4 ⊢ θ ↔ ψ
mdandyvrx7.5 ⊢ τ ↔ ψ
mdandyvrx7.6 ⊢ η ↔ φ
Assertion mdandyvrx7 ⊢ χ ⊻ σ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ ζ

Proof

Step Hyp Ref Expression
1 mdandyvrx7.1 ⊢ φ ⊻ ζ
2 mdandyvrx7.2 ⊢ ψ ⊻ σ
3 mdandyvrx7.3 ⊢ χ ↔ ψ
4 mdandyvrx7.4 ⊢ θ ↔ ψ
5 mdandyvrx7.5 ⊢ τ ↔ ψ
6 mdandyvrx7.6 ⊢ η ↔ φ
7 2 3 axorbciffatcxorb ⊢ χ ⊻ σ
8 2 4 axorbciffatcxorb ⊢ θ ⊻ σ
9 7 8 pm3.2i ⊢ χ ⊻ σ ∧ θ ⊻ σ
10 2 5 axorbciffatcxorb ⊢ τ ⊻ σ
11 9 10 pm3.2i ⊢ χ ⊻ σ ∧ θ ⊻ σ ∧ τ ⊻ σ
12 1 6 axorbciffatcxorb ⊢ η ⊻ ζ
13 11 12 pm3.2i ⊢ χ ⊻ σ ∧ θ ⊻ σ ∧ τ ⊻ σ ∧ η ⊻ ζ