Metamath Proof Explorer


Theorem mdslj2i

Description: Meet preservation of the reverse mapping between the two sublattices in Lemma 1.3 of MaedaMaeda p. 2. (Contributed by NM, 27-Apr-2006) (New usage is discouraged.)

Ref Expression
Hypotheses mdslle1.1 ⊢ A ∈ C ℋ
mdslle1.2 ⊢ B ∈ C ℋ
mdslle1.3 ⊢ C ∈ C ℋ
mdslle1.4 ⊢ D ∈ C ℋ
Assertion mdslj2i ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∩ D ∧ C ∨ ℋ D ⊆ B → C ∩ D ∨ ℋ A = C ∨ ℋ A ∩ D ∨ ℋ A

Proof

Step Hyp Ref Expression
1 mdslle1.1 ⊢ A ∈ C ℋ
2 mdslle1.2 ⊢ B ∈ C ℋ
3 mdslle1.3 ⊢ C ∈ C ℋ
4 mdslle1.4 ⊢ D ∈ C ℋ
5 3 4 1 lejdiri ⊢ C ∩ D ∨ ℋ A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A
6 5 a1i ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∩ D ∧ C ∨ ℋ D ⊆ B → C ∩ D ∨ ℋ A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A
7 ssin ⊢ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ↔ A ∩ B ⊆ C ∩ D
8 7 bicomi ⊢ A ∩ B ⊆ C ∩ D ↔ A ∩ B ⊆ C ∧ A ∩ B ⊆ D
9 3 4 2 chlubi ⊢ C ⊆ B ∧ D ⊆ B ↔ C ∨ ℋ D ⊆ B
10 9 bicomi ⊢ C ∨ ℋ D ⊆ B ↔ C ⊆ B ∧ D ⊆ B
11 8 10 anbi12i ⊢ A ∩ B ⊆ C ∩ D ∧ C ∨ ℋ D ⊆ B ↔ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B
12 simpr ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A → B 𝑀 ℋ * A
13 1 3 chub2i ⊢ A ⊆ C ∨ ℋ A
14 1 4 chub2i ⊢ A ⊆ D ∨ ℋ A
15 13 14 ssini ⊢ A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A
16 15 a1i ⊢ A ∩ B ⊆ C ∧ A ∩ B ⊆ D → A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A
17 3 2 1 chlej1i ⊢ C ⊆ B → C ∨ ℋ A ⊆ B ∨ ℋ A
18 2 1 chjcomi ⊢ B ∨ ℋ A = A ∨ ℋ B
19 17 18 sseqtrdi ⊢ C ⊆ B → C ∨ ℋ A ⊆ A ∨ ℋ B
20 ssinss1 ⊢ C ∨ ℋ A ⊆ A ∨ ℋ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ A ∨ ℋ B
21 19 20 syl ⊢ C ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ A ∨ ℋ B
22 21 adantr ⊢ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ A ∨ ℋ B
23 3 1 chjcli ⊢ C ∨ ℋ A ∈ C ℋ
24 4 1 chjcli ⊢ D ∨ ℋ A ∈ C ℋ
25 23 24 chincli ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ∈ C ℋ
26 1 2 25 3pm3.2i ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∨ ℋ A ∩ D ∨ ℋ A ∈ C ℋ
27 dmdsl3 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∨ ℋ A ∩ D ∨ ℋ A ∈ C ℋ ∧ B 𝑀 ℋ * A ∧ A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A ∧ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ A ∨ ℋ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∨ ℋ A = C ∨ ℋ A ∩ D ∨ ℋ A
28 26 27 mpan ⊢ B 𝑀 ℋ * A ∧ A ⊆ C ∨ ℋ A ∩ D ∨ ℋ A ∧ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ A ∨ ℋ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∨ ℋ A = C ∨ ℋ A ∩ D ∨ ℋ A
29 12 16 22 28 syl3an ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∨ ℋ A = C ∨ ℋ A ∩ D ∨ ℋ A
30 inss1 ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ C ∨ ℋ A
31 ssrin ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ C ∨ ℋ A → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ C ∨ ℋ A ∩ B
32 30 31 ax-mp ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ C ∨ ℋ A ∩ B
33 simpl ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A → A 𝑀 ℋ B
34 simpl ⊢ A ∩ B ⊆ C ∧ A ∩ B ⊆ D → A ∩ B ⊆ C
35 simpl ⊢ C ⊆ B ∧ D ⊆ B → C ⊆ B
36 1 2 3 3pm3.2i ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ
37 mdsl3 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ ∧ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ B → C ∨ ℋ A ∩ B = C
38 36 37 mpan ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ B → C ∨ ℋ A ∩ B = C
39 33 34 35 38 syl3an ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ B = C
40 32 39 sseqtrid ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ C
41 inss2 ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ D ∨ ℋ A
42 ssrin ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ⊆ D ∨ ℋ A → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ D ∨ ℋ A ∩ B
43 41 42 ax-mp ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ D ∨ ℋ A ∩ B
44 simpr ⊢ A ∩ B ⊆ C ∧ A ∩ B ⊆ D → A ∩ B ⊆ D
45 simpr ⊢ C ⊆ B ∧ D ⊆ B → D ⊆ B
46 1 2 4 3pm3.2i ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ D ∈ C ℋ
47 mdsl3 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ D ∈ C ℋ ∧ A 𝑀 ℋ B ∧ A ∩ B ⊆ D ∧ D ⊆ B → D ∨ ℋ A ∩ B = D
48 46 47 mpan ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ D ∧ D ⊆ B → D ∨ ℋ A ∩ B = D
49 33 44 45 48 syl3an ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → D ∨ ℋ A ∩ B = D
50 43 49 sseqtrid ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ D
51 40 50 ssind ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ C ∩ D
52 25 2 chincli ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∈ C ℋ
53 3 4 chincli ⊢ C ∩ D ∈ C ℋ
54 52 53 1 chlej1i ⊢ C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ⊆ C ∩ D → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∨ ℋ A ⊆ C ∩ D ∨ ℋ A
55 51 54 syl ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ∩ B ∨ ℋ A ⊆ C ∩ D ∨ ℋ A
56 29 55 eqsstrrd ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ C ∩ D ∨ ℋ A
57 56 3expb ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∧ A ∩ B ⊆ D ∧ C ⊆ B ∧ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ C ∩ D ∨ ℋ A
58 11 57 sylan2b ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∩ D ∧ C ∨ ℋ D ⊆ B → C ∨ ℋ A ∩ D ∨ ℋ A ⊆ C ∩ D ∨ ℋ A
59 6 58 eqssd ⊢ A 𝑀 ℋ B ∧ B 𝑀 ℋ * A ∧ A ∩ B ⊆ C ∩ D ∧ C ∨ ℋ D ⊆ B → C ∩ D ∨ ℋ A = C ∨ ℋ A ∩ D ∨ ℋ A