Metamath Proof Explorer


Theorem mdslmd4i

Description: Modular pair condition that implies the modular pair property in a sublattice. Lemma 1.5.2 of MaedaMaeda p. 2. (Contributed by NM, 24-Dec-2006) (New usage is discouraged.)

Ref Expression
Hypotheses mdslmd.1 ⊢ A ∈ C ℋ
mdslmd.2 ⊢ B ∈ C ℋ
mdslmd.3 ⊢ C ∈ C ℋ
mdslmd.4 ⊢ D ∈ C ℋ
Assertion mdslmd4i ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → C 𝑀 ℋ D

Proof

Step Hyp Ref Expression
1 mdslmd.1 ⊢ A ∈ C ℋ
2 mdslmd.2 ⊢ B ∈ C ℋ
3 mdslmd.3 ⊢ C ∈ C ℋ
4 mdslmd.4 ⊢ D ∈ C ℋ
5 simp1 ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → A 𝑀 ℋ B
6 1 2 chincli ⊢ A ∩ B ∈ C ℋ
7 ssmd1 ⊢ A ∩ B ∈ C ℋ ∧ D ∈ C ℋ ∧ A ∩ B ⊆ D → A ∩ B 𝑀 ℋ D
8 6 4 7 mp3an12 ⊢ A ∩ B ⊆ D → A ∩ B 𝑀 ℋ D
9 8 adantr ⊢ A ∩ B ⊆ D ∧ D ⊆ B → A ∩ B 𝑀 ℋ D
10 9 3ad2ant3 ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → A ∩ B 𝑀 ℋ D
11 sslin ⊢ D ⊆ B → A ∩ D ⊆ A ∩ B
12 sstr ⊢ A ∩ D ⊆ A ∩ B ∧ A ∩ B ⊆ C → A ∩ D ⊆ C
13 11 12 sylan ⊢ D ⊆ B ∧ A ∩ B ⊆ C → A ∩ D ⊆ C
14 13 ancoms ⊢ A ∩ B ⊆ C ∧ D ⊆ B → A ∩ D ⊆ C
15 14 ad2ant2rl ⊢ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → A ∩ D ⊆ C
16 15 3adant1 ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → A ∩ D ⊆ C
17 simp2r ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → C ⊆ A
18 1 2 4 3 mdslmd3i ⊢ A 𝑀 ℋ B ∧ A ∩ B 𝑀 ℋ D ∧ A ∩ D ⊆ C ∧ C ⊆ A → C 𝑀 ℋ B ∩ D
19 5 10 16 17 18 syl22anc ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → C 𝑀 ℋ B ∩ D
20 sseqin2 ⊢ D ⊆ B ↔ B ∩ D = D
21 20 bilani ⊢ A ∩ B ⊆ D ∧ D ⊆ B → B ∩ D = D
22 21 3ad2ant3 ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → B ∩ D = D
23 19 22 breqtrd ⊢ A 𝑀 ℋ B ∧ A ∩ B ⊆ C ∧ C ⊆ A ∧ A ∩ B ⊆ D ∧ D ⊆ B → C 𝑀 ℋ D