Metamath Proof Explorer


Theorem mirmid

Description: Point inversion preserves midpoints. (Contributed by Thierry Arnoux, 12-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
mirmid.s ⊢ S = pInv 𝒢 ⁡ G ⁡ M
mirmid.x ⊢ φ → M ∈ P
Assertion mirmid ⊢ φ → S ⁡ A mid 𝒢 ⁡ G S ⁡ B = S ⁡ A mid 𝒢 ⁡ G B

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 mirmid.s ⊢ S = pInv 𝒢 ⁡ G ⁡ M
9 mirmid.x ⊢ φ → M ∈ P
10 eqidd ⊢ φ → A mid 𝒢 ⁡ G B = A mid 𝒢 ⁡ G B
11 eqid ⊢ pInv 𝒢 ⁡ G = pInv 𝒢 ⁡ G
12 1 2 3 4 5 6 7 midcl ⊢ φ → A mid 𝒢 ⁡ G B ∈ P
13 1 2 3 4 5 6 7 11 12 ismidb ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ A mid 𝒢 ⁡ G B ⁡ A ↔ A mid 𝒢 ⁡ G B = A mid 𝒢 ⁡ G B
14 10 13 mpbird ⊢ φ → B = pInv 𝒢 ⁡ G ⁡ A mid 𝒢 ⁡ G B ⁡ A
15 14 fveq2d ⊢ φ → S ⁡ B = S ⁡ pInv 𝒢 ⁡ G ⁡ A mid 𝒢 ⁡ G B ⁡ A
16 eqid ⊢ Line 𝒢 ⁡ G = Line 𝒢 ⁡ G
17 1 2 3 16 11 4 9 8 6 12 mirmir2 ⊢ φ → S ⁡ pInv 𝒢 ⁡ G ⁡ A mid 𝒢 ⁡ G B ⁡ A = pInv 𝒢 ⁡ G ⁡ S ⁡ A mid 𝒢 ⁡ G B ⁡ S ⁡ A
18 15 17 eqtrd ⊢ φ → S ⁡ B = pInv 𝒢 ⁡ G ⁡ S ⁡ A mid 𝒢 ⁡ G B ⁡ S ⁡ A
19 1 2 3 16 11 4 9 8 6 mircl ⊢ φ → S ⁡ A ∈ P
20 1 2 3 16 11 4 9 8 7 mircl ⊢ φ → S ⁡ B ∈ P
21 1 2 3 16 11 4 9 8 12 mircl ⊢ φ → S ⁡ A mid 𝒢 ⁡ G B ∈ P
22 1 2 3 4 5 19 20 11 21 ismidb ⊢ φ → S ⁡ B = pInv 𝒢 ⁡ G ⁡ S ⁡ A mid 𝒢 ⁡ G B ⁡ S ⁡ A ↔ S ⁡ A mid 𝒢 ⁡ G S ⁡ B = S ⁡ A mid 𝒢 ⁡ G B
23 18 22 mpbid ⊢ φ → S ⁡ A mid 𝒢 ⁡ G S ⁡ B = S ⁡ A mid 𝒢 ⁡ G B