Metamath Proof Explorer


Theorem moi

Description: Equality implied by "at most one". (Contributed by NM, 18-Feb-2006)

Ref Expression
Hypotheses moi.1 ⊢ x = A → φ ↔ ψ
moi.2 ⊢ x = B → φ ↔ χ
Assertion moi ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ ∧ ψ ∧ χ → A = B

Proof

Step Hyp Ref Expression
1 moi.1 ⊢ x = A → φ ↔ ψ
2 moi.2 ⊢ x = B → φ ↔ χ
3 1 2 mob ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ ∧ ψ → A = B ↔ χ
4 3 biimprd ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ ∧ ψ → χ → A = B
5 4 3expia ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ → ψ → χ → A = B
6 5 impd ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ → ψ ∧ χ → A = B
7 6 3impia ⊢ A ∈ C ∧ B ∈ D ∧ ∃* x φ ∧ ψ ∧ χ → A = B