Metamath Proof Explorer


Theorem mon1pn0

Description: Monic polynomials are not zero. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses uc1pn0.p ⊢ P = Poly 1 ⁡ R
uc1pn0.z ⊢ 0 ˙ = 0 P
mon1pn0.m ⊢ M = Monic 1p ⁡ R
Assertion mon1pn0 ⊢ F ∈ M → F ≠ 0 ˙

Proof

Step Hyp Ref Expression
1 uc1pn0.p ⊢ P = Poly 1 ⁡ R
2 uc1pn0.z ⊢ 0 ˙ = 0 P
3 mon1pn0.m ⊢ M = Monic 1p ⁡ R
4 eqid ⊢ Base P = Base P
5 eqid ⊢ deg 1 ⁡ R = deg 1 ⁡ R
6 eqid ⊢ 1 R = 1 R
7 1 4 2 5 3 6 ismon1p ⊢ F ∈ M ↔ F ∈ Base P ∧ F ≠ 0 ˙ ∧ coe 1 ⁡ F ⁡ deg 1 ⁡ R ⁡ F = 1 R
8 7 simp2bi ⊢ F ∈ M → F ≠ 0 ˙