Metamath Proof Explorer


Theorem mulcxplem

Description: Lemma for mulcxp . (Contributed by Mario Carneiro, 2-Aug-2014)

Ref Expression
Hypotheses mulcxp.1 ⊢ φ → A ∈ ℂ
mulcxp.2 ⊢ φ → C ∈ ℂ
Assertion mulcxplem ⊢ φ → 0 C = A C ⁢ 0 C

Proof

Step Hyp Ref Expression
1 mulcxp.1 ⊢ φ → A ∈ ℂ
2 mulcxp.2 ⊢ φ → C ∈ ℂ
3 oveq2 ⊢ C = 0 → 0 C = 0 0
4 0cn ⊢ 0 ∈ ℂ
5 cxp0 ⊢ 0 ∈ ℂ → 0 0 = 1
6 4 5 ax-mp ⊢ 0 0 = 1
7 3 6 eqtrdi ⊢ C = 0 → 0 C = 1
8 oveq2 ⊢ C = 0 → A C = A 0
9 8 7 oveq12d ⊢ C = 0 → A C ⁢ 0 C = A 0 ⋅ 1
10 7 9 eqeq12d ⊢ C = 0 → 0 C = A C ⁢ 0 C ↔ 1 = A 0 ⋅ 1
11 cxpcl ⊢ A ∈ ℂ ∧ C ∈ ℂ → A C ∈ ℂ
12 1 2 11 syl2anc ⊢ φ → A C ∈ ℂ
13 12 adantr ⊢ φ ∧ C ≠ 0 → A C ∈ ℂ
14 13 mul01d ⊢ φ ∧ C ≠ 0 → A C ⋅ 0 = 0
15 0cxp ⊢ C ∈ ℂ ∧ C ≠ 0 → 0 C = 0
16 2 15 sylan ⊢ φ ∧ C ≠ 0 → 0 C = 0
17 16 oveq2d ⊢ φ ∧ C ≠ 0 → A C ⁢ 0 C = A C ⋅ 0
18 14 17 16 3eqtr4rd ⊢ φ ∧ C ≠ 0 → 0 C = A C ⁢ 0 C
19 cxp0 ⊢ A ∈ ℂ → A 0 = 1
20 1 19 syl ⊢ φ → A 0 = 1
21 20 oveq1d ⊢ φ → A 0 ⋅ 1 = 1 ⋅ 1
22 1t1e1 ⊢ 1 ⋅ 1 = 1
23 21 22 eqtr2di ⊢ φ → 1 = A 0 ⋅ 1
24 10 18 23 pm2.61ne ⊢ φ → 0 C = A C ⁢ 0 C