Metamath Proof Explorer


Theorem mulidnq

Description: Multiplication identity element for positive fractions. (Contributed by NM, 3-Mar-1996) (Revised by Mario Carneiro, 28-Apr-2013) (New usage is discouraged.)

Ref Expression
Assertion mulidnq A 𝑸 A 𝑸 1 𝑸 = A

Proof

Step Hyp Ref Expression
1 1nq 1 𝑸 𝑸
2 mulpqnq A 𝑸 1 𝑸 𝑸 A 𝑸 1 𝑸 = / 𝑸 A 𝑝𝑸 1 𝑸
3 1 2 mpan2 A 𝑸 A 𝑸 1 𝑸 = / 𝑸 A 𝑝𝑸 1 𝑸
4 relxp Rel 𝑵 × 𝑵
5 elpqn A 𝑸 A 𝑵 × 𝑵
6 1st2nd Rel 𝑵 × 𝑵 A 𝑵 × 𝑵 A = 1 st A 2 nd A
7 4 5 6 sylancr A 𝑸 A = 1 st A 2 nd A
8 df-1nq 1 𝑸 = 1 𝑜 1 𝑜
9 8 a1i A 𝑸 1 𝑸 = 1 𝑜 1 𝑜
10 7 9 oveq12d A 𝑸 A 𝑝𝑸 1 𝑸 = 1 st A 2 nd A 𝑝𝑸 1 𝑜 1 𝑜
11 xp1st A 𝑵 × 𝑵 1 st A 𝑵
12 5 11 syl A 𝑸 1 st A 𝑵
13 xp2nd A 𝑵 × 𝑵 2 nd A 𝑵
14 5 13 syl A 𝑸 2 nd A 𝑵
15 1pi 1 𝑜 𝑵
16 15 a1i A 𝑸 1 𝑜 𝑵
17 mulpipq 1 st A 𝑵 2 nd A 𝑵 1 𝑜 𝑵 1 𝑜 𝑵 1 st A 2 nd A 𝑝𝑸 1 𝑜 1 𝑜 = 1 st A 𝑵 1 𝑜 2 nd A 𝑵 1 𝑜
18 12 14 16 16 17 syl22anc A 𝑸 1 st A 2 nd A 𝑝𝑸 1 𝑜 1 𝑜 = 1 st A 𝑵 1 𝑜 2 nd A 𝑵 1 𝑜
19 mulidpi 1 st A 𝑵 1 st A 𝑵 1 𝑜 = 1 st A
20 11 19 syl A 𝑵 × 𝑵 1 st A 𝑵 1 𝑜 = 1 st A
21 mulidpi 2 nd A 𝑵 2 nd A 𝑵 1 𝑜 = 2 nd A
22 13 21 syl A 𝑵 × 𝑵 2 nd A 𝑵 1 𝑜 = 2 nd A
23 20 22 opeq12d A 𝑵 × 𝑵 1 st A 𝑵 1 𝑜 2 nd A 𝑵 1 𝑜 = 1 st A 2 nd A
24 5 23 syl A 𝑸 1 st A 𝑵 1 𝑜 2 nd A 𝑵 1 𝑜 = 1 st A 2 nd A
25 10 18 24 3eqtrd A 𝑸 A 𝑝𝑸 1 𝑸 = 1 st A 2 nd A
26 25 7 eqtr4d A 𝑸 A 𝑝𝑸 1 𝑸 = A
27 26 fveq2d A 𝑸 / 𝑸 A 𝑝𝑸 1 𝑸 = / 𝑸 A
28 nqerid A 𝑸 / 𝑸 A = A
29 3 27 28 3eqtrd A 𝑸 A 𝑸 1 𝑸 = A