Metamath Proof Explorer


Theorem mullt0b2d

Description: When the second term is negative, the first term is positive iff the product is negative. (Contributed by SN, 26-Nov-2025)

Ref Expression
Hypotheses mullt0b2d.a ⊢ φ → A ∈ ℝ
mullt0b2d.b ⊢ φ → B ∈ ℝ
mullt0b2d.1 ⊢ φ → B < 0
Assertion mullt0b2d ⊢ φ → 0 < A ↔ A ⁢ B < 0

Proof

Step Hyp Ref Expression
1 mullt0b2d.a ⊢ φ → A ∈ ℝ
2 mullt0b2d.b ⊢ φ → B ∈ ℝ
3 mullt0b2d.1 ⊢ φ → B < 0
4 simpr ⊢ φ ∧ 0 < A → 0 < A
5 4 gt0ne0d ⊢ φ ∧ 0 < A → A ≠ 0
6 3 adantr ⊢ φ ∧ 0 < A → B < 0
7 6 lt0ne0d ⊢ φ ∧ 0 < A → B ≠ 0
8 5 7 jca ⊢ φ ∧ 0 < A → A ≠ 0 ∧ B ≠ 0
9 neanior ⊢ A ≠ 0 ∧ B ≠ 0 ↔ ¬ A = 0 ∨ B = 0
10 8 9 sylib ⊢ φ ∧ 0 < A → ¬ A = 0 ∨ B = 0
11 1 adantr ⊢ φ ∧ 0 < A → A ∈ ℝ
12 2 adantr ⊢ φ ∧ 0 < A → B ∈ ℝ
13 11 12 sn-remul0ord ⊢ φ ∧ 0 < A → A ⁢ B = 0 ↔ A = 0 ∨ B = 0
14 10 13 mtbird ⊢ φ ∧ 0 < A → ¬ A ⁢ B = 0
15 0red ⊢ φ → 0 ∈ ℝ
16 2 15 3 ltnsymd ⊢ φ → ¬ 0 < B
17 16 adantr ⊢ φ ∧ 0 < A → ¬ 0 < B
18 11 12 4 mulgt0b1d ⊢ φ ∧ 0 < A → 0 < B ↔ 0 < A ⁢ B
19 17 18 mtbid ⊢ φ ∧ 0 < A → ¬ 0 < A ⁢ B
20 ioran ⊢ ¬ A ⁢ B = 0 ∨ 0 < A ⁢ B ↔ ¬ A ⁢ B = 0 ∧ ¬ 0 < A ⁢ B
21 14 19 20 sylanbrc ⊢ φ ∧ 0 < A → ¬ A ⁢ B = 0 ∨ 0 < A ⁢ B
22 1 2 remulcld ⊢ φ → A ⁢ B ∈ ℝ
23 22 15 lttrid ⊢ φ → A ⁢ B < 0 ↔ ¬ A ⁢ B = 0 ∨ 0 < A ⁢ B
24 23 adantr ⊢ φ ∧ 0 < A → A ⁢ B < 0 ↔ ¬ A ⁢ B = 0 ∨ 0 < A ⁢ B
25 21 24 mpbird ⊢ φ ∧ 0 < A → A ⁢ B < 0
26 remul02 ⊢ B ∈ ℝ → 0 ⋅ B = 0
27 2 26 syl ⊢ φ → 0 ⋅ B = 0
28 15 ltnrd ⊢ φ → ¬ 0 < 0
29 27 28 eqnbrtrd ⊢ φ → ¬ 0 ⋅ B < 0
30 oveq1 ⊢ 0 = A → 0 ⋅ B = A ⁢ B
31 30 breq1d ⊢ 0 = A → 0 ⋅ B < 0 ↔ A ⁢ B < 0
32 31 notbid ⊢ 0 = A → ¬ 0 ⋅ B < 0 ↔ ¬ A ⁢ B < 0
33 29 32 syl5ibcom ⊢ φ → 0 = A → ¬ A ⁢ B < 0
34 33 con2d ⊢ φ → A ⁢ B < 0 → ¬ 0 = A
35 34 imp ⊢ φ ∧ A ⁢ B < 0 → ¬ 0 = A
36 16 adantr ⊢ φ ∧ A ⁢ B < 0 → ¬ 0 < B
37 simplr ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → A ⁢ B < 0
38 1 ad2antrr ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → A ∈ ℝ
39 2 ad2antrr ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → B ∈ ℝ
40 simpr ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → A < 0
41 38 39 40 mullt0b1d ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → 0 < B ↔ A ⁢ B < 0
42 37 41 mpbird ⊢ φ ∧ A ⁢ B < 0 ∧ A < 0 → 0 < B
43 36 42 mtand ⊢ φ ∧ A ⁢ B < 0 → ¬ A < 0
44 ioran ⊢ ¬ 0 = A ∨ A < 0 ↔ ¬ 0 = A ∧ ¬ A < 0
45 35 43 44 sylanbrc ⊢ φ ∧ A ⁢ B < 0 → ¬ 0 = A ∨ A < 0
46 15 1 lttrid ⊢ φ → 0 < A ↔ ¬ 0 = A ∨ A < 0
47 46 adantr ⊢ φ ∧ A ⁢ B < 0 → 0 < A ↔ ¬ 0 = A ∨ A < 0
48 45 47 mpbird ⊢ φ ∧ A ⁢ B < 0 → 0 < A
49 25 48 impbida ⊢ φ → 0 < A ↔ A ⁢ B < 0