Metamath Proof Explorer


Theorem mvth

Description: The Mean Value Theorem. If F is a real continuous function on [ A , B ] which is differentiable on ( A , B ) , then there is some x e. ( A , B ) such that ( RR _D F )x is equal to the average slope over [ A , B ] . This is Metamath 100 proof #75. (Contributed by Mario Carneiro, 1-Sep-2014) (Proof shortened by Mario Carneiro, 29-Dec-2016)

Ref Expression
Hypotheses mvth.a ⊢ φ → A ∈ ℝ
mvth.b ⊢ φ → B ∈ ℝ
mvth.lt ⊢ φ → A < B
mvth.f ⊢ φ → F : A B ⟶cn ℝ
mvth.d ⊢ φ → dom ⁡ F ℝ ′ = A B
Assertion mvth ⊢ φ → ∃ x ∈ A B F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A B − A

Proof

Step Hyp Ref Expression
1 mvth.a ⊢ φ → A ∈ ℝ
2 mvth.b ⊢ φ → B ∈ ℝ
3 mvth.lt ⊢ φ → A < B
4 mvth.f ⊢ φ → F : A B ⟶cn ℝ
5 mvth.d ⊢ φ → dom ⁡ F ℝ ′ = A B
6 mptresid ⊢ I ↾ A B = z ∈ A B ⟼ z
7 iccssre ⊢ A ∈ ℝ ∧ B ∈ ℝ → A B ⊆ ℝ
8 1 2 7 syl2anc ⊢ φ → A B ⊆ ℝ
9 ax-resscn ⊢ ℝ ⊆ ℂ
10 cncfmptid ⊢ A B ⊆ ℝ ∧ ℝ ⊆ ℂ → z ∈ A B ⟼ z : A B ⟶cn ℝ
11 8 9 10 sylancl ⊢ φ → z ∈ A B ⟼ z : A B ⟶cn ℝ
12 6 11 eqeltrid ⊢ φ → I ↾ A B : A B ⟶cn ℝ
13 6 eqcomi ⊢ z ∈ A B ⟼ z = I ↾ A B
14 13 oveq2i ⊢ dz ∈ A B z d ℝ z = ℝ D I ↾ A B
15 reelprrecn ⊢ ℝ ∈ ℝ ℂ
16 15 a1i ⊢ φ → ℝ ∈ ℝ ℂ
17 simpr ⊢ φ ∧ z ∈ ℝ → z ∈ ℝ
18 17 recnd ⊢ φ ∧ z ∈ ℝ → z ∈ ℂ
19 1red ⊢ φ ∧ z ∈ ℝ → 1 ∈ ℝ
20 16 dvmptid ⊢ φ → dz ∈ ℝ z d ℝ z = z ∈ ℝ ⟼ 1
21 tgioo4 ⊢ topGen ⁡ ran ⁡ . = TopOpen ⁡ ℂ fld ↾ 𝑡 ℝ
22 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
23 iccntr ⊢ A ∈ ℝ ∧ B ∈ ℝ → int ⁡ topGen ⁡ ran ⁡ . ⁡ A B = A B
24 1 2 23 syl2anc ⊢ φ → int ⁡ topGen ⁡ ran ⁡ . ⁡ A B = A B
25 16 18 19 20 8 21 22 24 dvmptres2 ⊢ φ → dz ∈ A B z d ℝ z = z ∈ A B ⟼ 1
26 14 25 eqtr3id ⊢ φ → ℝ D I ↾ A B = z ∈ A B ⟼ 1
27 26 dmeqd ⊢ φ → dom ⁡ I ↾ A B ℝ ′ = dom ⁡ z ∈ A B ⟼ 1
28 1ex ⊢ 1 ∈ V
29 eqid ⊢ z ∈ A B ⟼ 1 = z ∈ A B ⟼ 1
30 28 29 dmmpti ⊢ dom ⁡ z ∈ A B ⟼ 1 = A B
31 27 30 eqtrdi ⊢ φ → dom ⁡ I ↾ A B ℝ ′ = A B
32 1 2 3 4 12 5 31 cmvth ⊢ φ → ∃ x ∈ A B F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x
33 1 rexrd ⊢ φ → A ∈ ℝ *
34 2 rexrd ⊢ φ → B ∈ ℝ *
35 1 2 3 ltled ⊢ φ → A ≤ B
36 ubicc2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A ≤ B → B ∈ A B
37 33 34 35 36 syl3anc ⊢ φ → B ∈ A B
38 fvresi ⊢ B ∈ A B → I ↾ A B ⁡ B = B
39 37 38 syl ⊢ φ → I ↾ A B ⁡ B = B
40 lbicc2 ⊢ A ∈ ℝ * ∧ B ∈ ℝ * ∧ A ≤ B → A ∈ A B
41 33 34 35 40 syl3anc ⊢ φ → A ∈ A B
42 fvresi ⊢ A ∈ A B → I ↾ A B ⁡ A = A
43 41 42 syl ⊢ φ → I ↾ A B ⁡ A = A
44 39 43 oveq12d ⊢ φ → I ↾ A B ⁡ B − I ↾ A B ⁡ A = B − A
45 44 adantr ⊢ φ ∧ x ∈ A B → I ↾ A B ⁡ B − I ↾ A B ⁡ A = B − A
46 45 oveq1d ⊢ φ ∧ x ∈ A B → I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x = B − A ⁢ F ℝ ′ ⁡ x
47 26 fveq1d ⊢ φ → I ↾ A B ℝ ′ ⁡ x = z ∈ A B ⟼ 1 ⁡ x
48 eqidd ⊢ z = x → 1 = 1
49 48 29 28 fvmpt3i ⊢ x ∈ A B → z ∈ A B ⟼ 1 ⁡ x = 1
50 47 49 sylan9eq ⊢ φ ∧ x ∈ A B → I ↾ A B ℝ ′ ⁡ x = 1
51 50 oveq2d ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = F ⁡ B − F ⁡ A ⋅ 1
52 cncff ⊢ F : A B ⟶cn ℝ → F : A B ⟶ ℝ
53 4 52 syl ⊢ φ → F : A B ⟶ ℝ
54 53 37 ffvelcdmd ⊢ φ → F ⁡ B ∈ ℝ
55 53 41 ffvelcdmd ⊢ φ → F ⁡ A ∈ ℝ
56 54 55 resubcld ⊢ φ → F ⁡ B − F ⁡ A ∈ ℝ
57 56 recnd ⊢ φ → F ⁡ B − F ⁡ A ∈ ℂ
58 57 adantr ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A ∈ ℂ
59 58 mulridd ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A ⋅ 1 = F ⁡ B − F ⁡ A
60 51 59 eqtrd ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = F ⁡ B − F ⁡ A
61 46 60 eqeq12d ⊢ φ ∧ x ∈ A B → I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x ↔ B − A ⁢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A
62 2 1 resubcld ⊢ φ → B − A ∈ ℝ
63 62 recnd ⊢ φ → B − A ∈ ℂ
64 63 adantr ⊢ φ ∧ x ∈ A B → B − A ∈ ℂ
65 dvf ⊢ F ℝ ′ : dom ⁡ F ℝ ′ ⟶ ℂ
66 5 feq2d ⊢ φ → F ℝ ′ : dom ⁡ F ℝ ′ ⟶ ℂ ↔ F ℝ ′ : A B ⟶ ℂ
67 65 66 mpbii ⊢ φ → F ℝ ′ : A B ⟶ ℂ
68 67 ffvelcdmda ⊢ φ ∧ x ∈ A B → F ℝ ′ ⁡ x ∈ ℂ
69 1 2 posdifd ⊢ φ → A < B ↔ 0 < B − A
70 3 69 mpbid ⊢ φ → 0 < B − A
71 70 gt0ne0d ⊢ φ → B − A ≠ 0
72 71 adantr ⊢ φ ∧ x ∈ A B → B − A ≠ 0
73 58 64 68 72 divmuld ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A B − A = F ℝ ′ ⁡ x ↔ B − A ⁢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A
74 61 73 bitr4d ⊢ φ ∧ x ∈ A B → I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x ↔ F ⁡ B − F ⁡ A B − A = F ℝ ′ ⁡ x
75 eqcom ⊢ F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x ↔ I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x
76 eqcom ⊢ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A B − A ↔ F ⁡ B − F ⁡ A B − A = F ℝ ′ ⁡ x
77 74 75 76 3bitr4g ⊢ φ ∧ x ∈ A B → F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x ↔ F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A B − A
78 77 rexbidva ⊢ φ → ∃ x ∈ A B F ⁡ B − F ⁡ A ⁢ I ↾ A B ℝ ′ ⁡ x = I ↾ A B ⁡ B − I ↾ A B ⁡ A ⁢ F ℝ ′ ⁡ x ↔ ∃ x ∈ A B F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A B − A
79 32 78 mpbid ⊢ φ → ∃ x ∈ A B F ℝ ′ ⁡ x = F ⁡ B − F ⁡ A B − A