Metamath Proof Explorer


Theorem nabbib

Description: Not equivalent wff's correspond to not equal class abstractions. (Contributed by AV, 7-Apr-2019) (Proof shortened by Wolf Lammen, 25-Nov-2019) Definitial form. (Revised by Wolf Lammen, 5-Mar-2025)

Ref Expression
Assertion nabbib ⊢ x | φ ≠ x | ψ ↔ ∃ x φ ↔ ¬ ψ

Proof

Step Hyp Ref Expression
1 df-ne ⊢ x | φ ≠ x | ψ ↔ ¬ x | φ = x | ψ
2 exnal ⊢ ∃ x ¬ φ ↔ ψ ↔ ¬ ∀ x φ ↔ ψ
3 xor3 ⊢ ¬ φ ↔ ψ ↔ φ ↔ ¬ ψ
4 3 exbii ⊢ ∃ x ¬ φ ↔ ψ ↔ ∃ x φ ↔ ¬ ψ
5 2 4 bitr3i ⊢ ¬ ∀ x φ ↔ ψ ↔ ∃ x φ ↔ ¬ ψ
6 abbib ⊢ x | φ = x | ψ ↔ ∀ x φ ↔ ψ
7 5 6 xchnxbir ⊢ ¬ x | φ = x | ψ ↔ ∃ x φ ↔ ¬ ψ
8 1 7 bitri ⊢ x | φ ≠ x | ψ ↔ ∃ x φ ↔ ¬ ψ