Metamath Proof Explorer


Theorem nbgr0vtx

Description: In a null graph (with no vertices), all neighborhoods are empty. (Contributed by AV, 15-Nov-2020) (Proof shortened by AV, 10-May-2025)

Ref Expression
Assertion nbgr0vtx Vtx G = G NeighbVtx K =

Proof

Step Hyp Ref Expression
1 nel02 Vtx G = ¬ K Vtx G
2 df-nel K Vtx G ¬ K Vtx G
3 1 2 sylibr Vtx G = K Vtx G
4 eqid Vtx G = Vtx G
5 4 nbgrnvtx0 K Vtx G G NeighbVtx K =
6 3 5 syl Vtx G = G NeighbVtx K =