Metamath Proof Explorer


Theorem ncolncol

Description: Deduce non-colinearity from non-colinearity and colinearity. (Contributed by Thierry Arnoux, 27-Aug-2019)

Ref Expression
Hypotheses tglineintmo.p ⊢ P = Base G
tglineintmo.i ⊢ I = Itv ⁡ G
tglineintmo.l ⊢ L = Line 𝒢 ⁡ G
tglineintmo.g ⊢ φ → G ∈ 𝒢 Tarski
tglineinteq.a ⊢ φ → A ∈ P
tglineinteq.b ⊢ φ → B ∈ P
tglineinteq.c ⊢ φ → C ∈ P
tglineinteq.d ⊢ φ → D ∈ P
tglineinteq.e ⊢ φ → ¬ A ∈ B L C ∨ B = C
ncolncol.1 ⊢ φ → D ∈ A L B
ncolncol.2 ⊢ φ → D ≠ B
Assertion ncolncol ⊢ φ → ¬ D ∈ B L C ∨ B = C

Proof

Step Hyp Ref Expression
1 tglineintmo.p ⊢ P = Base G
2 tglineintmo.i ⊢ I = Itv ⁡ G
3 tglineintmo.l ⊢ L = Line 𝒢 ⁡ G
4 tglineintmo.g ⊢ φ → G ∈ 𝒢 Tarski
5 tglineinteq.a ⊢ φ → A ∈ P
6 tglineinteq.b ⊢ φ → B ∈ P
7 tglineinteq.c ⊢ φ → C ∈ P
8 tglineinteq.d ⊢ φ → D ∈ P
9 tglineinteq.e ⊢ φ → ¬ A ∈ B L C ∨ B = C
10 ncolncol.1 ⊢ φ → D ∈ A L B
11 ncolncol.2 ⊢ φ → D ≠ B
12 4 adantr ⊢ φ ∧ D ∈ B L C ∨ B = C → G ∈ 𝒢 Tarski
13 5 adantr ⊢ φ ∧ D ∈ B L C ∨ B = C → A ∈ P
14 6 adantr ⊢ φ ∧ D ∈ B L C ∨ B = C → B ∈ P
15 7 adantr ⊢ φ ∧ D ∈ B L C ∨ B = C → C ∈ P
16 4 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → G ∈ 𝒢 Tarski
17 5 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → A ∈ P
18 6 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → B ∈ P
19 7 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ P
20 1 3 2 4 5 6 10 tglngne ⊢ φ → A ≠ B
21 20 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → A ≠ B
22 8 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → D ∈ P
23 11 necomd ⊢ φ → B ≠ D
24 23 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → B ≠ D
25 simpr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ D L B
26 1 2 3 16 18 22 19 24 25 lncom ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ B L D
27 20 necomd ⊢ φ → B ≠ A
28 1 2 3 4 6 5 8 27 10 lncom ⊢ φ → D ∈ B L A
29 1 2 3 4 6 5 27 8 11 28 tglineelsb2 ⊢ φ → B L A = B L D
30 29 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → B L A = B L D
31 26 30 eleqtrrd ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ B L A
32 1 2 3 16 17 18 19 21 31 lncom ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ A L B
33 32 orcd ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ C ∈ D L B → C ∈ A L B ∨ A = B
34 simpr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ D = B → D = B
35 11 ad2antrr ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ D = B → D ≠ B
36 34 35 pm2.21ddne ⊢ φ ∧ D ∈ B L C ∨ B = C ∧ D = B → C ∈ A L B ∨ A = B
37 8 adantr ⊢ φ ∧ D ∈ B L C ∨ B = C → D ∈ P
38 simpr ⊢ φ ∧ D ∈ B L C ∨ B = C → D ∈ B L C ∨ B = C
39 1 3 2 12 14 15 37 38 colrot2 ⊢ φ ∧ D ∈ B L C ∨ B = C → C ∈ D L B ∨ D = B
40 33 36 39 mpjaodan ⊢ φ ∧ D ∈ B L C ∨ B = C → C ∈ A L B ∨ A = B
41 1 3 2 12 13 14 15 40 colrot1 ⊢ φ ∧ D ∈ B L C ∨ B = C → A ∈ B L C ∨ B = C
42 9 41 mtand ⊢ φ → ¬ D ∈ B L C ∨ B = C