Metamath Proof Explorer


Theorem necon3bbid

Description: Deduction from equality to inequality. (Contributed by NM, 2-Jun-2007)

Ref Expression
Hypothesis necon3bbid.1 φ ψ A = B
Assertion necon3bbid φ ¬ ψ A B

Proof

Step Hyp Ref Expression
1 necon3bbid.1 φ ψ A = B
2 1 bicomd φ A = B ψ
3 2 necon3abid φ A B ¬ ψ
4 3 bicomd φ ¬ ψ A B