Metamath Proof Explorer
Description: Deduction for inequality. (Contributed by NM, 24-Jul-2012) (Proof
shortened by Wolf Lammen, 25-Nov-2019)
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|
Ref |
Expression |
|
Hypotheses |
neeq1d.1 |
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|
|
neeq12d.2 |
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|
Assertion |
neeq12d |
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Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
neeq1d.1 |
|
2 |
|
neeq12d.2 |
|
3 |
1 2
|
eqeq12d |
|
4 |
3
|
necon3bid |
|