Metamath Proof Explorer
Description: Deduction for inequality. (Contributed by NM, 25-Oct-1999) (Proof
shortened by Wolf Lammen, 19-Nov-2019)
|
|
Ref |
Expression |
|
Hypothesis |
neeq1d.1 |
|
|
Assertion |
neeq2d |
|
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
neeq1d.1 |
|
2 |
1
|
eqeq2d |
|
3 |
2
|
necon3bid |
|