Metamath Proof Explorer


Theorem neg2subd

Description: Relationship between subtraction and negative. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 φ A
pncand.2 φ B
Assertion neg2subd φ - A - B = B A

Proof

Step Hyp Ref Expression
1 negidd.1 φ A
2 pncand.2 φ B
3 neg2sub A B - A - B = B A
4 1 2 3 syl2anc φ - A - B = B A