Metamath Proof Explorer
Description: From the general negation of membership in A , infer that A is
the empty set. (Contributed by BJ, 6-Oct-2018)
|
|
Ref |
Expression |
|
Hypothesis |
nel0.1 |
|
|
Assertion |
nel0 |
|
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
nel0.1 |
|
| 2 |
|
eq0 |
|
| 3 |
2 1
|
mpgbir |
|