Metamath Proof Explorer


Theorem nexple

Description: A lower bound for an exponentiation. (Contributed by Thierry Arnoux, 19-Aug-2017)

Ref Expression
Assertion nexple ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B → A ≤ B A

Proof

Step Hyp Ref Expression
1 simpr ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A ∈ ℕ → A ∈ ℕ
2 simpl2 ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A ∈ ℕ → B ∈ ℝ
3 simpl3 ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A ∈ ℕ → 2 ≤ B
4 id ⊢ k = 1 → k = 1
5 oveq2 ⊢ k = 1 → B k = B 1
6 4 5 breq12d ⊢ k = 1 → k ≤ B k ↔ 1 ≤ B 1
7 6 imbi2d ⊢ k = 1 → B ∈ ℝ ∧ 2 ≤ B → k ≤ B k ↔ B ∈ ℝ ∧ 2 ≤ B → 1 ≤ B 1
8 id ⊢ k = n → k = n
9 oveq2 ⊢ k = n → B k = B n
10 8 9 breq12d ⊢ k = n → k ≤ B k ↔ n ≤ B n
11 10 imbi2d ⊢ k = n → B ∈ ℝ ∧ 2 ≤ B → k ≤ B k ↔ B ∈ ℝ ∧ 2 ≤ B → n ≤ B n
12 id ⊢ k = n + 1 → k = n + 1
13 oveq2 ⊢ k = n + 1 → B k = B n + 1
14 12 13 breq12d ⊢ k = n + 1 → k ≤ B k ↔ n + 1 ≤ B n + 1
15 14 imbi2d ⊢ k = n + 1 → B ∈ ℝ ∧ 2 ≤ B → k ≤ B k ↔ B ∈ ℝ ∧ 2 ≤ B → n + 1 ≤ B n + 1
16 id ⊢ k = A → k = A
17 oveq2 ⊢ k = A → B k = B A
18 16 17 breq12d ⊢ k = A → k ≤ B k ↔ A ≤ B A
19 18 imbi2d ⊢ k = A → B ∈ ℝ ∧ 2 ≤ B → k ≤ B k ↔ B ∈ ℝ ∧ 2 ≤ B → A ≤ B A
20 simpl ⊢ B ∈ ℝ ∧ 2 ≤ B → B ∈ ℝ
21 1nn0 ⊢ 1 ∈ ℕ 0
22 21 a1i ⊢ B ∈ ℝ ∧ 2 ≤ B → 1 ∈ ℕ 0
23 1red ⊢ B ∈ ℝ ∧ 2 ≤ B → 1 ∈ ℝ
24 2re ⊢ 2 ∈ ℝ
25 24 a1i ⊢ B ∈ ℝ ∧ 2 ≤ B → 2 ∈ ℝ
26 1le2 ⊢ 1 ≤ 2
27 26 a1i ⊢ B ∈ ℝ ∧ 2 ≤ B → 1 ≤ 2
28 simpr ⊢ B ∈ ℝ ∧ 2 ≤ B → 2 ≤ B
29 23 25 20 27 28 letrd ⊢ B ∈ ℝ ∧ 2 ≤ B → 1 ≤ B
30 20 22 29 expge1d ⊢ B ∈ ℝ ∧ 2 ≤ B → 1 ≤ B 1
31 simp1 ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ∈ ℕ
32 31 nnred ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ∈ ℝ
33 1red ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 1 ∈ ℝ
34 32 33 readdcld ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ∈ ℝ
35 20 3ad2ant2 ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → B ∈ ℝ
36 32 35 remulcld ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ⁢ B ∈ ℝ
37 31 nnnn0d ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ∈ ℕ 0
38 35 37 reexpcld ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → B n ∈ ℝ
39 38 35 remulcld ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → B n ⁢ B ∈ ℝ
40 24 a1i ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 2 ∈ ℝ
41 32 40 remulcld ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ⋅ 2 ∈ ℝ
42 31 nnge1d ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 1 ≤ n
43 33 32 32 42 leadd2dd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ≤ n + n
44 32 recnd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ∈ ℂ
45 44 times2d ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ⋅ 2 = n + n
46 43 45 breqtrrd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ≤ n ⋅ 2
47 37 nn0ge0d ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 0 ≤ n
48 simp2r ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 2 ≤ B
49 40 35 32 47 48 lemul2ad ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ⋅ 2 ≤ n ⁢ B
50 34 41 36 46 49 letrd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ≤ n ⁢ B
51 0red ⊢ B ∈ ℝ ∧ 2 ≤ B → 0 ∈ ℝ
52 0le2 ⊢ 0 ≤ 2
53 52 a1i ⊢ B ∈ ℝ ∧ 2 ≤ B → 0 ≤ 2
54 51 25 20 53 28 letrd ⊢ B ∈ ℝ ∧ 2 ≤ B → 0 ≤ B
55 54 3ad2ant2 ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → 0 ≤ B
56 simp3 ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ≤ B n
57 32 38 35 55 56 lemul1ad ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n ⁢ B ≤ B n ⁢ B
58 34 36 39 50 57 letrd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ≤ B n ⁢ B
59 35 recnd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → B ∈ ℂ
60 59 37 expp1d ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → B n + 1 = B n ⁢ B
61 58 60 breqtrrd ⊢ n ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B ∧ n ≤ B n → n + 1 ≤ B n + 1
62 61 3exp ⊢ n ∈ ℕ → B ∈ ℝ ∧ 2 ≤ B → n ≤ B n → n + 1 ≤ B n + 1
63 62 a2d ⊢ n ∈ ℕ → B ∈ ℝ ∧ 2 ≤ B → n ≤ B n → B ∈ ℝ ∧ 2 ≤ B → n + 1 ≤ B n + 1
64 7 11 15 19 30 63 nnind ⊢ A ∈ ℕ → B ∈ ℝ ∧ 2 ≤ B → A ≤ B A
65 64 3impib ⊢ A ∈ ℕ ∧ B ∈ ℝ ∧ 2 ≤ B → A ≤ B A
66 1 2 3 65 syl3anc ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A ∈ ℕ → A ≤ B A
67 0le1 ⊢ 0 ≤ 1
68 67 a1i ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → 0 ≤ 1
69 simpr ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → A = 0
70 69 oveq2d ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → B A = B 0
71 simpl2 ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → B ∈ ℝ
72 71 recnd ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → B ∈ ℂ
73 72 exp0d ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → B 0 = 1
74 70 73 eqtrd ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → B A = 1
75 68 69 74 3brtr4d ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B ∧ A = 0 → A ≤ B A
76 elnn0 ⊢ A ∈ ℕ 0 ↔ A ∈ ℕ ∨ A = 0
77 76 biimpi ⊢ A ∈ ℕ 0 → A ∈ ℕ ∨ A = 0
78 77 3ad2ant1 ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B → A ∈ ℕ ∨ A = 0
79 66 75 78 mpjaodan ⊢ A ∈ ℕ 0 ∧ B ∈ ℝ ∧ 2 ≤ B → A ≤ B A