Metamath Proof Explorer


Theorem nf3or

Description: If x is not free in ph , ps , and ch , then it is not free in ( ph \/ ps \/ ch ) . (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypotheses nf.1 ⊢ Ⅎ x φ
nf.2 ⊢ Ⅎ x ψ
nf.3 ⊢ Ⅎ x χ
Assertion nf3or ⊢ Ⅎ x φ ∨ ψ ∨ χ

Proof

Step Hyp Ref Expression
1 nf.1 ⊢ Ⅎ x φ
2 nf.2 ⊢ Ⅎ x ψ
3 nf.3 ⊢ Ⅎ x χ
4 df-3or ⊢ φ ∨ ψ ∨ χ ↔ φ ∨ ψ ∨ χ
5 1 2 nfor ⊢ Ⅎ x φ ∨ ψ
6 5 3 nfor ⊢ Ⅎ x φ ∨ ψ ∨ χ
7 4 6 nfxfr ⊢ Ⅎ x φ ∨ ψ ∨ χ