Metamath Proof Explorer


Theorem nfeqf1

Description: An equation between setvar is free of any other setvar. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by Wolf Lammen, 10-Jun-2019) (New usage is discouraged.)

Ref Expression
Assertion nfeqf1 ¬ x x = y x y = z

Proof

Step Hyp Ref Expression
1 nfeqf2 ¬ x x = y x z = y
2 equcom z = y y = z
3 2 nfbii x z = y x y = z
4 1 3 sylib ¬ x x = y x y = z