Metamath Proof Explorer


Theorem nfeqf2

Description: An equation between setvar is free of any other setvar. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by Wolf Lammen, 9-Jun-2019) Remove dependency on ax-12 . (Revised by Wolf Lammen, 16-Dec-2022) (New usage is discouraged.)

Ref Expression
Assertion nfeqf2 ⊢ ¬ ∀ x x = y → Ⅎ x z = y

Proof

Step Hyp Ref Expression
1 exnal ⊢ ∃ x ¬ x = y ↔ ¬ ∀ x x = y
2 hbe1 ⊢ ∃ x z = y → ∀ x ∃ x z = y
3 ax13lem2 ⊢ ¬ x = y → ∃ x z = y → z = y
4 ax13lem1 ⊢ ¬ x = y → z = y → ∀ x z = y
5 3 4 syldc ⊢ ∃ x z = y → ¬ x = y → ∀ x z = y
6 2 5 eximdh ⊢ ∃ x z = y → ∃ x ¬ x = y → ∃ x ∀ x z = y
7 hbe1a ⊢ ∃ x ∀ x z = y → ∀ x z = y
8 6 7 syl6com ⊢ ∃ x ¬ x = y → ∃ x z = y → ∀ x z = y
9 8 nfd ⊢ ∃ x ¬ x = y → Ⅎ x z = y
10 1 9 sylbir ⊢ ¬ ∀ x x = y → Ⅎ x z = y