Metamath Proof Explorer


Theorem nfpconfp

Description: The set of fixed points of F is the complement of the set of points moved by F . (Contributed by Thierry Arnoux, 17-Nov-2023)

Ref Expression
Assertion nfpconfp ⊢ F Fn A → A ∖ dom ⁡ F ∖ I = dom ⁡ F ∩ I

Proof

Step Hyp Ref Expression
1 eldif ⊢ x ∈ A ∖ dom ⁡ F ∖ I ↔ x ∈ A ∧ ¬ x ∈ dom ⁡ F ∖ I
2 fnelfp ⊢ F Fn A ∧ x ∈ A → x ∈ dom ⁡ F ∩ I ↔ F ⁡ x = x
3 2 pm5.32da ⊢ F Fn A → x ∈ A ∧ x ∈ dom ⁡ F ∩ I ↔ x ∈ A ∧ F ⁡ x = x
4 inss1 ⊢ F ∩ I ⊆ F
5 dmss ⊢ F ∩ I ⊆ F → dom ⁡ F ∩ I ⊆ dom ⁡ F
6 4 5 ax-mp ⊢ dom ⁡ F ∩ I ⊆ dom ⁡ F
7 fndm ⊢ F Fn A → dom ⁡ F = A
8 6 7 sseqtrid ⊢ F Fn A → dom ⁡ F ∩ I ⊆ A
9 8 sseld ⊢ F Fn A → x ∈ dom ⁡ F ∩ I → x ∈ A
10 9 pm4.71rd ⊢ F Fn A → x ∈ dom ⁡ F ∩ I ↔ x ∈ A ∧ x ∈ dom ⁡ F ∩ I
11 fnelnfp ⊢ F Fn A ∧ x ∈ A → x ∈ dom ⁡ F ∖ I ↔ F ⁡ x ≠ x
12 11 notbid ⊢ F Fn A ∧ x ∈ A → ¬ x ∈ dom ⁡ F ∖ I ↔ ¬ F ⁡ x ≠ x
13 nne ⊢ ¬ F ⁡ x ≠ x ↔ F ⁡ x = x
14 12 13 bitrdi ⊢ F Fn A ∧ x ∈ A → ¬ x ∈ dom ⁡ F ∖ I ↔ F ⁡ x = x
15 14 pm5.32da ⊢ F Fn A → x ∈ A ∧ ¬ x ∈ dom ⁡ F ∖ I ↔ x ∈ A ∧ F ⁡ x = x
16 3 10 15 3bitr4rd ⊢ F Fn A → x ∈ A ∧ ¬ x ∈ dom ⁡ F ∖ I ↔ x ∈ dom ⁡ F ∩ I
17 1 16 bitrid ⊢ F Fn A → x ∈ A ∖ dom ⁡ F ∖ I ↔ x ∈ dom ⁡ F ∩ I
18 17 eqrdv ⊢ F Fn A → A ∖ dom ⁡ F ∖ I = dom ⁡ F ∩ I