Metamath Proof Explorer


Theorem nn0sqeq1

Description: A natural number with square one is equal to one. (Contributed by Thierry Arnoux, 2-Feb-2020) (Proof shortened by Thierry Arnoux, 6-Jun-2023)

Ref Expression
Assertion nn0sqeq1 ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → N = 1

Proof

Step Hyp Ref Expression
1 simpr ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → N 2 = 1
2 1 fveq2d ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → N 2 = 1
3 nn0re ⊢ N ∈ ℕ 0 → N ∈ ℝ
4 nn0ge0 ⊢ N ∈ ℕ 0 → 0 ≤ N
5 sqrtsq ⊢ N ∈ ℝ ∧ 0 ≤ N → N 2 = N
6 3 4 5 syl2anc ⊢ N ∈ ℕ 0 → N 2 = N
7 6 adantr ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → N 2 = N
8 sqrt1 ⊢ 1 = 1
9 8 a1i ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → 1 = 1
10 2 7 9 3eqtr3d ⊢ N ∈ ℕ 0 ∧ N 2 = 1 → N = 1