Metamath Proof Explorer


Theorem nnawordi

Description: Adding to both sides of an inequality in _om . (Contributed by Scott Fenton, 16-Apr-2012) (Revised by Mario Carneiro, 12-May-2012)

Ref Expression
Assertion nnawordi ⊢ A ∈ ω ∧ B ∈ ω ∧ C ∈ ω → A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ x = ∅ → A + 𝑜 x = A + 𝑜 ∅
2 oveq2 ⊢ x = ∅ → B + 𝑜 x = B + 𝑜 ∅
3 1 2 sseq12d ⊢ x = ∅ → A + 𝑜 x ⊆ B + 𝑜 x ↔ A + 𝑜 ∅ ⊆ B + 𝑜 ∅
4 3 imbi2d ⊢ x = ∅ → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ⊆ B → A + 𝑜 ∅ ⊆ B + 𝑜 ∅
5 4 imbi2d ⊢ x = ∅ → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 ∅ ⊆ B + 𝑜 ∅
6 oveq2 ⊢ x = y → A + 𝑜 x = A + 𝑜 y
7 oveq2 ⊢ x = y → B + 𝑜 x = B + 𝑜 y
8 6 7 sseq12d ⊢ x = y → A + 𝑜 x ⊆ B + 𝑜 x ↔ A + 𝑜 y ⊆ B + 𝑜 y
9 8 imbi2d ⊢ x = y → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ⊆ B → A + 𝑜 y ⊆ B + 𝑜 y
10 9 imbi2d ⊢ x = y → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 y ⊆ B + 𝑜 y
11 oveq2 ⊢ x = suc ⁡ y → A + 𝑜 x = A + 𝑜 suc ⁡ y
12 oveq2 ⊢ x = suc ⁡ y → B + 𝑜 x = B + 𝑜 suc ⁡ y
13 11 12 sseq12d ⊢ x = suc ⁡ y → A + 𝑜 x ⊆ B + 𝑜 x ↔ A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
14 13 imbi2d ⊢ x = suc ⁡ y → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ⊆ B → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
15 14 imbi2d ⊢ x = suc ⁡ y → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
16 oveq2 ⊢ x = C → A + 𝑜 x = A + 𝑜 C
17 oveq2 ⊢ x = C → B + 𝑜 x = B + 𝑜 C
18 16 17 sseq12d ⊢ x = C → A + 𝑜 x ⊆ B + 𝑜 x ↔ A + 𝑜 C ⊆ B + 𝑜 C
19 18 imbi2d ⊢ x = C → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C
20 19 imbi2d ⊢ x = C → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 x ⊆ B + 𝑜 x ↔ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C
21 nnon ⊢ A ∈ ω → A ∈ On
22 nnon ⊢ B ∈ ω → B ∈ On
23 oa0 ⊢ A ∈ On → A + 𝑜 ∅ = A
24 23 adantr ⊢ A ∈ On ∧ B ∈ On → A + 𝑜 ∅ = A
25 oa0 ⊢ B ∈ On → B + 𝑜 ∅ = B
26 25 adantl ⊢ A ∈ On ∧ B ∈ On → B + 𝑜 ∅ = B
27 24 26 sseq12d ⊢ A ∈ On ∧ B ∈ On → A + 𝑜 ∅ ⊆ B + 𝑜 ∅ ↔ A ⊆ B
28 27 biimprd ⊢ A ∈ On ∧ B ∈ On → A ⊆ B → A + 𝑜 ∅ ⊆ B + 𝑜 ∅
29 21 22 28 syl2an ⊢ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 ∅ ⊆ B + 𝑜 ∅
30 nnacl ⊢ A ∈ ω ∧ y ∈ ω → A + 𝑜 y ∈ ω
31 30 ancoms ⊢ y ∈ ω ∧ A ∈ ω → A + 𝑜 y ∈ ω
32 31 adantrr ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A + 𝑜 y ∈ ω
33 nnon ⊢ A + 𝑜 y ∈ ω → A + 𝑜 y ∈ On
34 eloni ⊢ A + 𝑜 y ∈ On → Ord ⁡ A + 𝑜 y
35 32 33 34 3syl ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → Ord ⁡ A + 𝑜 y
36 nnacl ⊢ B ∈ ω ∧ y ∈ ω → B + 𝑜 y ∈ ω
37 36 ancoms ⊢ y ∈ ω ∧ B ∈ ω → B + 𝑜 y ∈ ω
38 37 adantrl ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → B + 𝑜 y ∈ ω
39 nnon ⊢ B + 𝑜 y ∈ ω → B + 𝑜 y ∈ On
40 eloni ⊢ B + 𝑜 y ∈ On → Ord ⁡ B + 𝑜 y
41 38 39 40 3syl ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → Ord ⁡ B + 𝑜 y
42 ordsucsssuc ⊢ Ord ⁡ A + 𝑜 y ∧ Ord ⁡ B + 𝑜 y → A + 𝑜 y ⊆ B + 𝑜 y ↔ suc ⁡ A + 𝑜 y ⊆ suc ⁡ B + 𝑜 y
43 35 41 42 syl2anc ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A + 𝑜 y ⊆ B + 𝑜 y ↔ suc ⁡ A + 𝑜 y ⊆ suc ⁡ B + 𝑜 y
44 43 biimpa ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω ∧ A + 𝑜 y ⊆ B + 𝑜 y → suc ⁡ A + 𝑜 y ⊆ suc ⁡ B + 𝑜 y
45 nnasuc ⊢ A ∈ ω ∧ y ∈ ω → A + 𝑜 suc ⁡ y = suc ⁡ A + 𝑜 y
46 45 ancoms ⊢ y ∈ ω ∧ A ∈ ω → A + 𝑜 suc ⁡ y = suc ⁡ A + 𝑜 y
47 46 adantrr ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A + 𝑜 suc ⁡ y = suc ⁡ A + 𝑜 y
48 nnasuc ⊢ B ∈ ω ∧ y ∈ ω → B + 𝑜 suc ⁡ y = suc ⁡ B + 𝑜 y
49 48 ancoms ⊢ y ∈ ω ∧ B ∈ ω → B + 𝑜 suc ⁡ y = suc ⁡ B + 𝑜 y
50 49 adantrl ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → B + 𝑜 suc ⁡ y = suc ⁡ B + 𝑜 y
51 47 50 sseq12d ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y ↔ suc ⁡ A + 𝑜 y ⊆ suc ⁡ B + 𝑜 y
52 51 adantr ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω ∧ A + 𝑜 y ⊆ B + 𝑜 y → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y ↔ suc ⁡ A + 𝑜 y ⊆ suc ⁡ B + 𝑜 y
53 44 52 mpbird ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω ∧ A + 𝑜 y ⊆ B + 𝑜 y → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
54 53 ex ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A + 𝑜 y ⊆ B + 𝑜 y → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
55 54 imim2d ⊢ y ∈ ω ∧ A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 y ⊆ B + 𝑜 y → A ⊆ B → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
56 55 ex ⊢ y ∈ ω → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 y ⊆ B + 𝑜 y → A ⊆ B → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
57 56 a2d ⊢ y ∈ ω → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 y ⊆ B + 𝑜 y → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 suc ⁡ y ⊆ B + 𝑜 suc ⁡ y
58 5 10 15 20 29 57 finds ⊢ C ∈ ω → A ∈ ω ∧ B ∈ ω → A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C
59 58 com12 ⊢ A ∈ ω ∧ B ∈ ω → C ∈ ω → A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C
60 59 3impia ⊢ A ∈ ω ∧ B ∈ ω ∧ C ∈ ω → A ⊆ B → A + 𝑜 C ⊆ B + 𝑜 C