Metamath Proof Explorer


Theorem npcans

Description: Cancellation law for surreal subtraction. (Contributed by Scott Fenton, 4-Feb-2025)

Ref Expression
Assertion npcans ⊢ A ∈ No ∧ B ∈ No → A - s B + s B = A

Proof

Step Hyp Ref Expression
1 subscl ⊢ A ∈ No ∧ B ∈ No → A - s B ∈ No
2 simpr ⊢ A ∈ No ∧ B ∈ No → B ∈ No
3 1 2 addscomd ⊢ A ∈ No ∧ B ∈ No → A - s B + s B = B + s A - s B
4 pncan3s ⊢ B ∈ No ∧ A ∈ No → B + s A - s B = A
5 4 ancoms ⊢ A ∈ No ∧ B ∈ No → B + s A - s B = A
6 3 5 eqtrd ⊢ A ∈ No ∧ B ∈ No → A - s B + s B = A