Metamath Proof Explorer


Theorem numma

Description: Perform a multiply-add of two decimal integers M and N against a fixed multiplicand P (no carry). (Contributed by Mario Carneiro, 18-Feb-2014)

Ref Expression
Hypotheses numma.1 ⊢ T ∈ ℕ 0
numma.2 ⊢ A ∈ ℕ 0
numma.3 ⊢ B ∈ ℕ 0
numma.4 ⊢ C ∈ ℕ 0
numma.5 ⊢ D ∈ ℕ 0
numma.6 ⊢ M = T ⁢ A + B
numma.7 ⊢ N = T ⁢ C + D
numma.8 ⊢ P ∈ ℕ 0
numma.9 ⊢ A ⁢ P + C = E
numma.10 ⊢ B ⁢ P + D = F
Assertion numma ⊢ M ⁢ P + N = T ⁢ E + F

Proof

Step Hyp Ref Expression
1 numma.1 ⊢ T ∈ ℕ 0
2 numma.2 ⊢ A ∈ ℕ 0
3 numma.3 ⊢ B ∈ ℕ 0
4 numma.4 ⊢ C ∈ ℕ 0
5 numma.5 ⊢ D ∈ ℕ 0
6 numma.6 ⊢ M = T ⁢ A + B
7 numma.7 ⊢ N = T ⁢ C + D
8 numma.8 ⊢ P ∈ ℕ 0
9 numma.9 ⊢ A ⁢ P + C = E
10 numma.10 ⊢ B ⁢ P + D = F
11 6 oveq1i ⊢ M ⁢ P = T ⁢ A + B ⁢ P
12 11 7 oveq12i ⊢ M ⁢ P + N = T ⁢ A + B ⁢ P + T ⁢ C + D
13 1 nn0cni ⊢ T ∈ ℂ
14 2 nn0cni ⊢ A ∈ ℂ
15 8 nn0cni ⊢ P ∈ ℂ
16 14 15 mulcli ⊢ A ⁢ P ∈ ℂ
17 4 nn0cni ⊢ C ∈ ℂ
18 13 16 17 adddii ⊢ T ⁢ A ⁢ P + C = T ⁢ A ⁢ P + T ⁢ C
19 13 14 15 mulassi ⊢ T ⁢ A ⁢ P = T ⁢ A ⁢ P
20 19 oveq1i ⊢ T ⁢ A ⁢ P + T ⁢ C = T ⁢ A ⁢ P + T ⁢ C
21 18 20 eqtr4i ⊢ T ⁢ A ⁢ P + C = T ⁢ A ⁢ P + T ⁢ C
22 21 oveq1i ⊢ T ⁢ A ⁢ P + C + B ⁢ P + D = T ⁢ A ⁢ P + T ⁢ C + B ⁢ P + D
23 13 14 mulcli ⊢ T ⁢ A ∈ ℂ
24 3 nn0cni ⊢ B ∈ ℂ
25 23 24 15 adddiri ⊢ T ⁢ A + B ⁢ P = T ⁢ A ⁢ P + B ⁢ P
26 25 oveq1i ⊢ T ⁢ A + B ⁢ P + T ⁢ C + D = T ⁢ A ⁢ P + B ⁢ P + T ⁢ C + D
27 23 15 mulcli ⊢ T ⁢ A ⁢ P ∈ ℂ
28 13 17 mulcli ⊢ T ⁢ C ∈ ℂ
29 24 15 mulcli ⊢ B ⁢ P ∈ ℂ
30 5 nn0cni ⊢ D ∈ ℂ
31 27 28 29 30 add4i ⊢ T ⁢ A ⁢ P + T ⁢ C + B ⁢ P + D = T ⁢ A ⁢ P + B ⁢ P + T ⁢ C + D
32 26 31 eqtr4i ⊢ T ⁢ A + B ⁢ P + T ⁢ C + D = T ⁢ A ⁢ P + T ⁢ C + B ⁢ P + D
33 22 32 eqtr4i ⊢ T ⁢ A ⁢ P + C + B ⁢ P + D = T ⁢ A + B ⁢ P + T ⁢ C + D
34 9 oveq2i ⊢ T ⁢ A ⁢ P + C = T ⁢ E
35 34 10 oveq12i ⊢ T ⁢ A ⁢ P + C + B ⁢ P + D = T ⁢ E + F
36 12 33 35 3eqtr2i ⊢ M ⁢ P + N = T ⁢ E + F