Metamath Proof Explorer


Theorem numma2c

Description: Perform a multiply-add of two decimal integers M and N against a fixed multiplicand P (with carry). (Contributed by Mario Carneiro, 18-Feb-2014)

Ref Expression
Hypotheses numma.1 ⊢ T ∈ ℕ 0
numma.2 ⊢ A ∈ ℕ 0
numma.3 ⊢ B ∈ ℕ 0
numma.4 ⊢ C ∈ ℕ 0
numma.5 ⊢ D ∈ ℕ 0
numma.6 ⊢ M = T ⁢ A + B
numma.7 ⊢ N = T ⁢ C + D
numma2c.8 ⊢ P ∈ ℕ 0
numma2c.9 ⊢ F ∈ ℕ 0
numma2c.10 ⊢ G ∈ ℕ 0
numma2c.11 ⊢ P ⁢ A + C + G = E
numma2c.12 ⊢ P ⁢ B + D = T ⁢ G + F
Assertion numma2c ⊢ P ⋅ M + N = T ⁢ E + F

Proof

Step Hyp Ref Expression
1 numma.1 ⊢ T ∈ ℕ 0
2 numma.2 ⊢ A ∈ ℕ 0
3 numma.3 ⊢ B ∈ ℕ 0
4 numma.4 ⊢ C ∈ ℕ 0
5 numma.5 ⊢ D ∈ ℕ 0
6 numma.6 ⊢ M = T ⁢ A + B
7 numma.7 ⊢ N = T ⁢ C + D
8 numma2c.8 ⊢ P ∈ ℕ 0
9 numma2c.9 ⊢ F ∈ ℕ 0
10 numma2c.10 ⊢ G ∈ ℕ 0
11 numma2c.11 ⊢ P ⁢ A + C + G = E
12 numma2c.12 ⊢ P ⁢ B + D = T ⁢ G + F
13 8 nn0cni ⊢ P ∈ ℂ
14 1 2 3 numcl ⊢ T ⁢ A + B ∈ ℕ 0
15 6 14 eqeltri ⊢ M ∈ ℕ 0
16 15 nn0cni ⊢ M ∈ ℂ
17 13 16 mulcomi ⊢ P ⋅ M = M ⁢ P
18 17 oveq1i ⊢ P ⋅ M + N = M ⁢ P + N
19 2 nn0cni ⊢ A ∈ ℂ
20 19 13 mulcomi ⊢ A ⁢ P = P ⁢ A
21 20 oveq1i ⊢ A ⁢ P + C + G = P ⁢ A + C + G
22 21 11 eqtri ⊢ A ⁢ P + C + G = E
23 3 nn0cni ⊢ B ∈ ℂ
24 23 13 mulcomi ⊢ B ⁢ P = P ⁢ B
25 24 oveq1i ⊢ B ⁢ P + D = P ⁢ B + D
26 25 12 eqtri ⊢ B ⁢ P + D = T ⁢ G + F
27 1 2 3 4 5 6 7 8 9 10 22 26 nummac ⊢ M ⁢ P + N = T ⁢ E + F
28 18 27 eqtri ⊢ P ⋅ M + N = T ⁢ E + F